Virtual Lab Questions 4.00 ppm P 0.82 a. Compare the magnetic character, bond lengths, bond orders, bond dissociation energies, and Urine sample 0.625 relative ionization energies for N2, N2", and N22, using the Molecular Orbital Theory. b. For the molecule selenium tetrafluoride, SeF4, provide a Lewis structure and the hybridization of the central atom. Sketch the species, showing all bond types (identical to that shown in lectures, such as o(1s, sp3)) and bond angles. Name the geometry about the central atom. 3.
Formal Charges
Formal charges have an important role in organic chemistry since this concept helps us to know whether an atom in a molecule is neutral/bears a positive or negative charge. Even if some molecules are neutral, the atoms within that molecule need not be neutral atoms.
Polarity Of Water
In simple chemical terms, polarity refers to the separation of charges in a chemical species leading into formation of two polar ends which are positively charged end and negatively charged end. Polarity in any molecule occurs due to the differences in the electronegativities of the bonded atoms. Water, as we all know has two hydrogen atoms bonded to an oxygen atom. As oxygen is more electronegative than hydrogen thus, there exists polarity in the bonds which is why water is known as a polar solvent.
Valence Bond Theory Vbt
Valence bond theory (VBT) in simple terms explains how individual atomic orbitals with an unpaired electron each, come close to each other and overlap to form a molecular orbital giving a covalent bond. It gives a quantum mechanical approach to the formation of covalent bonds with the help of wavefunctions using attractive and repulsive energies when two atoms are brought from infinity to their internuclear distance.
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Virtual Lab Question: A solution of 0.0040 M copper dithizone transmits 66 % of the lisht
1.
particular wavelength in a cell of 1.5 cm thickness. What is the absorbance? What is the mela
absorptivity? What is the concentration of a copper dithizone solution that transmits 20 % under the
same conditions?
Virtual Lab Question: Phosphorus in urine can be determined by treating with molybdenum (VI) and
then reducing the phosphomolybdo complex with aminonaphtholsulfonic acid to give the
characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270 mL of urine
in 24 hours and the pH of the urine was 6.5. A 1.00 mL aliquot of the urine was treated with
molybdate reagent and aminonaphtholsulfonic acid and was diluted to a volume of 50.0 ml
A series of phosphate standards were similarly treated. The absorbance of the solutions at 690 nm.
measured against a blank, were as follows:
Solution
Absorbance
a. Calculate the number of grams of phosphorus
excreted per day.
1.00ppm P
0.205
b. Calculate the phosphorus concentration in the urine
2.00 ppm P
0.41
as millimoles per liter.
3.00 ppm P
0.615
3.
Virtual Lab Questions
a. Compare the magnetic character, bond lengths,
4.00 ppm P
0.82
bond orders, bond dissociation energies, and
Urine sample
0.625
relative ionization energies for N2, N2", and N2²",
using the Molecular Orbital Theory.
b. For the molecule selenium tetrafluoride, SeF4, provide a Lewis structure and the hybridization
of the central atom. Sketch the species, showing all bond types (identical to that shown in
lectures, such as o(1s, sp3)) and bond angles. Name the geometry about the central atom.
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