Via ultrasound, it is determined that a cat will have a litter containing 8 kittens. The sexes of the kittens are stillunknown. Assume each kitten born has a 53% chance of being female. The random variable X = "the number ofmale kittens in the litter" has a Binomial distribution with n = 8 and p = 0.47.Determine the variance of the random quantity: 7X - 86. Var( 7X - 86 ) =Round your answer to 2 decimal places.

Answered: Via ultrasound, it is determined that a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a batch of metal shafts produced in a manufacturing company have a variance of 9 and a mean diameter of 207 inches. If 72 shafts are sampled at random from the batch, what is the probability that the mean diameter of the sample shafts would differ from the population mean by less than 0.3 inches? Round your answer to four decimal places.
A sample has a minimum value of 7 and a maximum value of 58 .Estimate its variance.
X is a random variable with mean X = 3, variance o = 2.
Suppose a sample of n = 160 observations has a mean of 13.6 and a variance of 6.8. If each value in the sample is multiplied by 4 and then 20 is added, what would be the variance of the new sample values?
A company is doing a hypothesis test on the variation in quality from two suppliers. Both distributions are normal, and the populations are independent. Use a = 0.05. A sample of 31 products were selected from Supplier 1 and a standard deviation of quality was found to be 3.77. A sample of 16 products were selected from Supplier 2 and a standard deviation of quality was found to be 3.5659. Test to see if the variance in quality for Supplier 1 is larger than Supplier 2. What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: 0.² H₁: 0.² Based on the hypotheses, compute the following: Round answers to at least 4 decimal places. The test statistic is = The p-value is = The decision is to [Fail to reject the null hypothesis The correct summary would be: There is not enough evidence to support the claim in quality for Supplier 1 is larger than Supplier 2. o that the variance
Suppose that the variance of the sample mean is equals 25 and the sample size is 6 . then the population variance is
One sample has n = 10 scores and a variance of s2 = 20, and a second sample has n = 15 scores and a variance of s2 = 30. What can you conclude about the pooled variance for these two samples?
Find the variance of the data
Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…
A researcher is interested whether a new drug is effective in changing patients' cholesterol levels. She divided 33 patients into 3 groups according to the dosage the patient received. The cholesterol levels of all patients are measured and used as the data for the Analysis of Variance (ANOVA). If she reported the test statistic F = 2.1 What is the degree of freedom for the numerator of the F statistic? What is the degree of freedom for the denominator of the F statistic? What is the P-value of the F-test? (Round to 3 decimals) Given the significance level of 0.01, what can she conclude from the test? *The patients in differnt groups have simliar average cholesterial levels. The drug made no difference. *At least one group of patients have an average cholesterol level that is different from the other groups. The drug may have an effect.
If the highest 8o of students in the final exam were rewarded. The mean for this exam was 120 & the variance was 289. What was the lowest mark that has been rewarded for? minimum mark-? Select one: 143.8 143.97 NONE 143.885
It is possible to have a variance of 625,000625,000 for some data set. true or false

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