Vhich of the following statements about the following reaction is correct? C4H2O42 + H2O C,H¾O;²- AG° = -3.25 kJ/mol a) Since AG> 0, Keq is less than 1, and the reaction favors products. )) Since AG> 0, Keq is greater than 1, and the reaction favors reactants. c) Since AG < 0, Keq is less than 1, and the reaction favors reactants. 1) Since AG < 0, Keq is less than 1, and the reaction favors reactants. e) Since AG < 0, Keq is greater than 1, and the reaction favors products.

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**Question:** Which of the following statements about the following reaction is correct?

\[ \text{C}_4\text{H}_2\text{O}_4^{2-} + \text{H}_2\text{O} \rightleftharpoons \text{C}_4\text{H}_4\text{O}_5^{2-} \quad \Delta G^\circ = -3.25 \, \text{kJ/mol} \]

**Options:**

(a) Since \( \Delta G > 0 \), \( K_{eq} \) is less than 1, and the reaction favors products.

(b) Since \( \Delta G > 0 \), \( K_{eq} \) is greater than 1, and the reaction favors reactants.

(c) Since \( \Delta G < 0 \), \( K_{eq} \) is less than 1, and the reaction favors reactants.

(d) Since \( \Delta G < 0 \), \( K_{eq} \) is less than 1, and the reaction favors reactants.

(e) Since \( \Delta G < 0 \), \( K_{eq} \) is greater than 1, and the reaction favors products.

**Explanation:**

Given \( \Delta G^\circ = -3.25 \, \text{kJ/mol} \), this indicates the reaction is spontaneous under standard conditions. A negative \( \Delta G \) suggests:

- \( K_{eq} > 1 \) because the formation of products is favored at equilibrium.
- Therefore, option (e) is the correct statement: "Since \( \Delta G < 0 \), \( K_{eq} \) is greater than 1, and the reaction favors products."
Transcribed Image Text:**Question:** Which of the following statements about the following reaction is correct? \[ \text{C}_4\text{H}_2\text{O}_4^{2-} + \text{H}_2\text{O} \rightleftharpoons \text{C}_4\text{H}_4\text{O}_5^{2-} \quad \Delta G^\circ = -3.25 \, \text{kJ/mol} \] **Options:** (a) Since \( \Delta G > 0 \), \( K_{eq} \) is less than 1, and the reaction favors products. (b) Since \( \Delta G > 0 \), \( K_{eq} \) is greater than 1, and the reaction favors reactants. (c) Since \( \Delta G < 0 \), \( K_{eq} \) is less than 1, and the reaction favors reactants. (d) Since \( \Delta G < 0 \), \( K_{eq} \) is less than 1, and the reaction favors reactants. (e) Since \( \Delta G < 0 \), \( K_{eq} \) is greater than 1, and the reaction favors products. **Explanation:** Given \( \Delta G^\circ = -3.25 \, \text{kJ/mol} \), this indicates the reaction is spontaneous under standard conditions. A negative \( \Delta G \) suggests: - \( K_{eq} > 1 \) because the formation of products is favored at equilibrium. - Therefore, option (e) is the correct statement: "Since \( \Delta G < 0 \), \( K_{eq} \) is greater than 1, and the reaction favors products."
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