How many moles of Hz are required to produce-3751 kJ of heat in the following reaction? N: (g) +3 H2 (g)→2 NHs (g) AH° = -91.8 kJ/mol

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**Question:**

How many moles of H₂ are required to produce -3751 kJ of heat in the following reaction? 

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)  ΔH° = -91.8 kJ/mol

**Explanation:**

The reaction described is the synthesis of ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂) gas. The enthalpy change (ΔH°) for this reaction is -91.8 kJ/mol, indicating that the reaction releases 91.8 kJ of heat for every mole of N₂ that reacts (or equivalently for every 2 moles of NH₃ produced).

To determine how many moles of H₂ are required to produce -3751 kJ of heat, one must set up a proportion based on the enthalpy change:

- From the balanced equation: 3 moles of H₂ produce -91.8 kJ.
- Therefore, to produce -3751 kJ, calculate the moles of H₂ needed using the ratio:

    \[
    \frac{-3751 \, \text{kJ}}{-91.8 \, \text{kJ/mol}} = \text{moles of N₂ reacted}
    \]

- Since each mole of N₂ requires 3 moles of H₂:

    \[
    \text{Moles of H₂ needed} = 3 \times \text{moles of N₂ reacted}
    \]
Transcribed Image Text:**Question:** How many moles of H₂ are required to produce -3751 kJ of heat in the following reaction? N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ΔH° = -91.8 kJ/mol **Explanation:** The reaction described is the synthesis of ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂) gas. The enthalpy change (ΔH°) for this reaction is -91.8 kJ/mol, indicating that the reaction releases 91.8 kJ of heat for every mole of N₂ that reacts (or equivalently for every 2 moles of NH₃ produced). To determine how many moles of H₂ are required to produce -3751 kJ of heat, one must set up a proportion based on the enthalpy change: - From the balanced equation: 3 moles of H₂ produce -91.8 kJ. - Therefore, to produce -3751 kJ, calculate the moles of H₂ needed using the ratio: \[ \frac{-3751 \, \text{kJ}}{-91.8 \, \text{kJ/mol}} = \text{moles of N₂ reacted} \] - Since each mole of N₂ requires 3 moles of H₂: \[ \text{Moles of H₂ needed} = 3 \times \text{moles of N₂ reacted} \]
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