7. When 0.63 g of solid LiCI (AHsoln = – 37.1 kJ/mol) dissolves in 5 L of water, how much heat is released?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### Problem Statement:

When 0.63 g of solid LiCl (ΔHₛₒₗₙ = -37.1 kJ/mol) dissolves in 5 L of water, how much heat is released?

### Explanation:

This is a thermochemistry problem where you need to determine the heat released when lithium chloride (LiCl) dissolves in water. The enthalpy change of solution, ΔHₛₒₗₙ, is provided as -37.1 kJ/mol, indicating an exothermic process (heat is released).

To solve this, follow these steps:

1. **Calculate the Moles of LiCl:**
   - Use the molar mass of LiCl to convert grams to moles.

2. **Use ΔHₛₒₗₙ to Find Heat Released:**
   - Multiply the moles of LiCl by the given ΔHₛₒₗₙ to find the total heat released.

This type of calculation is essential in understanding energy changes in chemical processes.
Transcribed Image Text:### Problem Statement: When 0.63 g of solid LiCl (ΔHₛₒₗₙ = -37.1 kJ/mol) dissolves in 5 L of water, how much heat is released? ### Explanation: This is a thermochemistry problem where you need to determine the heat released when lithium chloride (LiCl) dissolves in water. The enthalpy change of solution, ΔHₛₒₗₙ, is provided as -37.1 kJ/mol, indicating an exothermic process (heat is released). To solve this, follow these steps: 1. **Calculate the Moles of LiCl:** - Use the molar mass of LiCl to convert grams to moles. 2. **Use ΔHₛₒₗₙ to Find Heat Released:** - Multiply the moles of LiCl by the given ΔHₛₒₗₙ to find the total heat released. This type of calculation is essential in understanding energy changes in chemical processes.
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