Vhere possible, classify these systems as reactant-favored or product-favored at 298 K. If the direction cannot be determined rom the information given, classify the reaction as "Insufficient information." Reactant-favored Product-favored Insufficient information A(s)+B(g) = 2 C(g) AH° = -109 kJ 2 A(g) + 2 B(g) 5 C(g) AH° = +313 kJ 2 A(g) + 2 B(g) 3 C(g) 2 A(g) + 3 B(g) 4 C(g) AH° = -95 kJ AH° = +254 kJ Answer Bank
Vhere possible, classify these systems as reactant-favored or product-favored at 298 K. If the direction cannot be determined rom the information given, classify the reaction as "Insufficient information." Reactant-favored Product-favored Insufficient information A(s)+B(g) = 2 C(g) AH° = -109 kJ 2 A(g) + 2 B(g) 5 C(g) AH° = +313 kJ 2 A(g) + 2 B(g) 3 C(g) 2 A(g) + 3 B(g) 4 C(g) AH° = -95 kJ AH° = +254 kJ Answer Bank
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Where possible, classify these systems as reactant-favored or product-favored at 298 K. If the direction cannot be determined
from the information given, classify the reaction as "Insufficient information."
Reactant-favored
Product-favored
Insufficient information
A(s)+B(g) = 2C(g)
2 A(g) + 2 B(g) 5 C(g)
AH° = -109 kJ
AH° = +313 kJ
2 A(g) + 2 B(g) 3 C(g)
2 A(g) + 3 B(g) =4 C(g)
AH° = +254 kJ
AH° = -95 kJ
Answer Bank](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64a30517-e863-4662-9804-11d4230920b7%2Fc06e8863-7872-4e53-926f-45fb825b5455%2F0p6p0a5_processed.png&w=3840&q=75)
Transcribed Image Text:Where possible, classify these systems as reactant-favored or product-favored at 298 K. If the direction cannot be determined
from the information given, classify the reaction as "Insufficient information."
Reactant-favored
Product-favored
Insufficient information
A(s)+B(g) = 2C(g)
2 A(g) + 2 B(g) 5 C(g)
AH° = -109 kJ
AH° = +313 kJ
2 A(g) + 2 B(g) 3 C(g)
2 A(g) + 3 B(g) =4 C(g)
AH° = +254 kJ
AH° = -95 kJ
Answer Bank
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