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Using values from Appendix C of your textbook, calculate the value of Keq at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCI(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 X (c) 4 NH3(g) + O₂(g) ⇒2 N₂H4(9) + 2 H₂O(1) Keq = 5.51e15

Using values from Appendix C of your textbook, calculate the value of Keq at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCI(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 X (c) 4 NH3(g) + O₂(g) ⇒2 N₂H4(9) + 2 H₂O(1) Keq = 5.51e15

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using values from Appendix C of your textbook, calculate the value of Keg at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCl(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 x. (c) 4 NH3(g) + O₂(g) 2 N₂H₂(g) + 2 H₂O(1) Keq = 5.51e15
Transcribed Image Text:Using values from Appendix C of your textbook, calculate the value of Keg at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCl(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 x. (c) 4 NH3(g) + O₂(g) 2 N₂H₂(g) + 2 H₂O(1) Keq = 5.51e15
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