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Verify and derive the following equation Y(t) = 1 √1-520 √1-521+ +tan (7.18) 5 To derive Eq. (7.18), use is made of the techniques of Chap. 3. Since <1, Eqs. (7.15) to (7.17) indicate a pair of complex conjugate roots in the left half-plane and a root at the origin. In terms of the symbols of Fig. 3-1, the complex roots correspond to s2 and s and the root at the origin to 56. The reader should realize that in Eq. (7.18), the argument of the sine function is in radians, as is the value of the inverse tangent term. By referring to Table 3.1. we see that Y(t) has the form

Verify and derive the following equation Y(t) = 1 √1-520 √1-521+ +tan (7.18) 5 To derive Eq. (7.18), use is made of the techniques of Chap. 3. Since <1, Eqs. (7.15) to (7.17) indicate a pair of complex conjugate roots in the left half-plane and a root at the origin. In terms of the symbols of Fig. 3-1, the complex roots correspond to s2 and s and the root at the origin to 56. The reader should realize that in Eq. (7.18), the argument of the sine function is in radians, as is the value of the inverse tangent term. By referring to Table 3.1. we see that Y(t) has the form

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Verify and derive the following equation Y(t) = 1 √1-520 √1-521+ +tan (7.18) 5 To derive Eq. (7.18), use is made of the techniques of Chap. 3. Since <1, Eqs. (7.15) to (7.17) indicate a pair of complex conjugate roots in the left half-plane and a root at the origin. In terms of the symbols of Fig. 3-1, the complex roots correspond to s2 and s and the root at the origin to 56. The reader should realize that in Eq. (7.18), the argument of the sine function is in radians, as is the value of the inverse tangent term. By referring to Table 3.1. we see that Y(t) has the form
Transcribed Image Text:Verify and derive the following equation Y(t) = 1 √1-520 √1-521+ +tan (7.18) 5 To derive Eq. (7.18), use is made of the techniques of Chap. 3. Since <1, Eqs. (7.15) to (7.17) indicate a pair of complex conjugate roots in the left half-plane and a root at the origin. In terms of the symbols of Fig. 3-1, the complex roots correspond to s2 and s and the root at the origin to 56. The reader should realize that in Eq. (7.18), the argument of the sine function is in radians, as is the value of the inverse tangent term. By referring to Table 3.1. we see that Y(t) has the form
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