Velocity (m/s) 25 20 5m 15 10 5 50 m 25 m 20 m Time (s) The velocity-time graph above represents the motion of an accelerating car. What is the displacement of the car between t=0 and t=5? 100 m Velocity (m/s) vs. Time (s) 05 Highlight Hotspot 2 3 5

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Chapter1: Units, Trigonometry. And Vectors
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**Question 04: Multiple Choice**

**Velocity (m/s) vs. Time (s) Graph Explanation**

The graph displays the relationship between velocity (in meters per second) and time (in seconds) for an accelerating car. The velocity increases linearly from 0 m/s at 0 seconds to 25 m/s at 5 seconds.

**Graph Details:**

- **X-axis (Horizontal):** Represents time in seconds (s), ranging from 0 to 5.
- **Y-axis (Vertical):** Represents velocity in meters per second (m/s), ranging from 0 to 25.
- **Line:** A straight line that starts at the origin (0,0) and ends at the point (5,25), indicating uniform acceleration.

**Problem Statement:**

The velocity-time graph above represents the motion of an accelerating car. What is the displacement of the car between t=0 and t=5?

**Options:**

- ○ 50 m
- ● 5 m
- ○ 20 m
- ○ 25 m
- ○ 100 m

**Note:** The highlighted option is "5 m."
Transcribed Image Text:**Question 04: Multiple Choice** **Velocity (m/s) vs. Time (s) Graph Explanation** The graph displays the relationship between velocity (in meters per second) and time (in seconds) for an accelerating car. The velocity increases linearly from 0 m/s at 0 seconds to 25 m/s at 5 seconds. **Graph Details:** - **X-axis (Horizontal):** Represents time in seconds (s), ranging from 0 to 5. - **Y-axis (Vertical):** Represents velocity in meters per second (m/s), ranging from 0 to 25. - **Line:** A straight line that starts at the origin (0,0) and ends at the point (5,25), indicating uniform acceleration. **Problem Statement:** The velocity-time graph above represents the motion of an accelerating car. What is the displacement of the car between t=0 and t=5? **Options:** - ○ 50 m - ● 5 m - ○ 20 m - ○ 25 m - ○ 100 m **Note:** The highlighted option is "5 m."
Expert Solution
Step 1

Displacement is given as the area under velocity time graph.

Let displacement = x 

(Given, 

 Height of triangle, v = 20 m/s 

Base of triangle, t = 5 s )

 

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