State and derive the Work-Energy Theorem.
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A: Since you have asked multiple part question, so we will answer the first three parts for you.…
Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…
A: Given data: Mass (m) = 65.0 kg Distance (d) = 5.00 m Frictional force (f) = 75.0 N g = 10.0 m/s2…
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Q: State the Work-Energy theorem/equation (words and equations).
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Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…
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Q: 11.) A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…
A: Given Data: Cabinet Mass, m=65 kg Ramp distance, d=5 m Friction, f=75 N Inclination angle is 15°…
Q: 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The friction…
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A: We know the formula of work W= F × S Where F =Force S= displacement
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- Show and explain the complete solution with the formulas. Label the symbols used accordingly.Two people pull a block on a rough horizontal surface. One suggests to use a rope that is inclined at angle 70° and another suggests to use a rope at angle 20°. If they pull for the same horizontal distance with the same strength of force, which person does more work? At the end of the same distance pulled, which block is moving faster? Instead, the surface over which the blocks move is now frictionless. How does this change your answers to the questions above?Use the work energy principle to calculate how far the car will travel before stopping. How far would the car travel if it were going twice as fast?
- A crane lifts a 300.0 kg load at constant speed at a vertical distance of 30.0 m in 10 seconds. Calculate the rate at which the crane is doing work on the load. Show the free body diagram.3) The figure below illustrates a skier who is skiing on a large frictionless spherical ball of snow. The skier can be treated as a point-like object. The skier starts at the top of the ball with very little speed and picks up speed while traveling along the surface of the snow. During this time, the only forces acting on the skier are the gravitational force applied by the Earth and the normal force applied by the snow. At the moment the radial line extending from the skier to the center of the ball defines an angle a with respect to a vertical line, the skier is about to lose contact with the ball. Determine the value of a.sum of the other two forces. The force the worker applies is constant over the distance and is equal to the value F. 4) A cart of mass m1 reaches the bottom of a ramp with an angle 0, going a speed v, and is pulled to the top of a ramp on the cart along the ramp by X Joules (Hint: This means you can write an equation relating the applied force to the at neight n with an applied force that exceeds the work done bv the force of friction plus the work done by gravity e m the space below the necessary diagrams to approach all parts of this problem (there should be two). b) Find an equation for the speed of the cart at the top of the ramp.
- Calculate the work done (in J) by a 75.0 kg man who pushes a crate 4.30 m up along a ramp that makes an angle of 20.0° with the horizontal. (See the figure below.) He exerts a force of 540 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp.Please see attached image for question. Thank youcalculate the work
- Lee pushes horizontally with a force of 68 Non a 25 kg mass for 30 m across a floor.Calculate the amount of work Lee did.Answer in units of J.When do you use W = Fdcostheta when solving for work and in what situations will you use W = Fd?A 3500 lb SUV is traveling at 30 mph up a 6% slope when the engine quits. Use work and energy to determine the distance traveled until the vehicle comes to rest (at which point the parking brake is applied). Assume drag forces are negligible.