How much work is done lifting a 25 pound object from the ground to the top of a 55 foot butlding i the cable used weighs 0.5 pounds per foot? foot pounds. Question Help: Video Submit Question
How much work is done lifting a 25 pound object from the ground to the top of a 55 foot butlding i the cable used weighs 0.5 pounds per foot? foot pounds. Question Help: Video Submit Question
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Energy Of A System
Section: Chapter Questions
Problem 7.2CQ: Object 1 pushes on object 2 as the objects move together, like a bulldozer pushing a stone. Assume...
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![Title: Calculating Work Done Using Forces and Distances
**Problem Statement:**
How much work is done lifting a 25-pound object from the ground to the top of a 55-foot building if the cable used weighs 0.5 pounds per foot?
**Answer Field:**
[ Text Input Box ]
foot-pounds.
**Additional Help:**
[ Video Button: Question Help ]
**Submission:**
[ Submit Question Button ]
**Explanation:**
To solve this problem, you can use the formula for work done:
\[ W = F \times d \]
Where:
- \( W \) is the work done.
- \( F \) is the force applied.
- \( d \) is the distance over which the force is applied.
In this specific problem:
- The object weighs 25 pounds.
- The distance is 55 feet.
- The cable itself has a weight of 0.5 pounds per foot, contributing additional weight as it lifts the object.
The total weight to be lifted increases linearly with height due to the weight of the cable. At the top of the building, the total weight lifted is the weight of the object plus the weight of the entire cable.
To find the total work done, you can integrate the force along the height of the building. Here's a detailed approach:
\[ \text{Total Work Done} = \int_0^{55} (25 + 0.5x) \, dx \]
Where \( x \) is the height in feet.
Solving this integral will provide you the total work in foot-pounds.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4f75436-93ee-4e58-a0e3-afe0fa0e1ea5%2Fd5820bfa-2d71-4793-95ec-8a956559c6c9%2Fkwtmvtq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Title: Calculating Work Done Using Forces and Distances
**Problem Statement:**
How much work is done lifting a 25-pound object from the ground to the top of a 55-foot building if the cable used weighs 0.5 pounds per foot?
**Answer Field:**
[ Text Input Box ]
foot-pounds.
**Additional Help:**
[ Video Button: Question Help ]
**Submission:**
[ Submit Question Button ]
**Explanation:**
To solve this problem, you can use the formula for work done:
\[ W = F \times d \]
Where:
- \( W \) is the work done.
- \( F \) is the force applied.
- \( d \) is the distance over which the force is applied.
In this specific problem:
- The object weighs 25 pounds.
- The distance is 55 feet.
- The cable itself has a weight of 0.5 pounds per foot, contributing additional weight as it lifts the object.
The total weight to be lifted increases linearly with height due to the weight of the cable. At the top of the building, the total weight lifted is the weight of the object plus the weight of the entire cable.
To find the total work done, you can integrate the force along the height of the building. Here's a detailed approach:
\[ \text{Total Work Done} = \int_0^{55} (25 + 0.5x) \, dx \]
Where \( x \) is the height in feet.
Solving this integral will provide you the total work in foot-pounds.
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