Value Correct D.P. Mass of calorimeter, (g) 28.4563 Matches expected D.P. Mass of calorimeter + water, (g) 29.4531 Matches expected D.P. Mass of calorimeter + water + acid, (g) 30.1236 Matches expected D.P. Mass of calorimeter + water + acid + base, (g) 33.3215 Matches expected D.P. Mass of water + acid + base, (g) 4.8652 C4. TEMPERATURE Value Correct D.P. Initial temp, T;. (°C) 18.5 Matches expected D.P. Final temp, T¡. ("C) 20.6 Matches expected D.P. AT. ("C) 2.1 C5. MOLES Unrounded Rounded Moles of acid, (mol) Moles of base, (mol) Limiting reactant: >
Value Correct D.P. Mass of calorimeter, (g) 28.4563 Matches expected D.P. Mass of calorimeter + water, (g) 29.4531 Matches expected D.P. Mass of calorimeter + water + acid, (g) 30.1236 Matches expected D.P. Mass of calorimeter + water + acid + base, (g) 33.3215 Matches expected D.P. Mass of water + acid + base, (g) 4.8652 C4. TEMPERATURE Value Correct D.P. Initial temp, T;. (°C) 18.5 Matches expected D.P. Final temp, T¡. ("C) 20.6 Matches expected D.P. AT. ("C) 2.1 C5. MOLES Unrounded Rounded Moles of acid, (mol) Moles of base, (mol) Limiting reactant: >
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Find the moles of acid and base with the rounded and ungrounded and also the limiting reactant
Expert Solution
Step 1
Given:
Mass of calorimeter = 28.4563 g
Mass of calorimeter + water = 29.4551 g
Mass of calorimeter + water + acid = 30.1236 g
Mass of calorimeter + water + acid + base = 33.3215 g
molar mass of acid (H2SO4) = 98.08 g/mol
molar mass of acid (NaOH) = 40.0 g/mol
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