V₁= Soo Lov ・IND: 9.7 Z₁ 102 H # #r 2052 £90 JIDO ) ( 80 + 1707 from Hoat •400 50.2 3002 2T = 73.422 -37.409⁰ ✓ n b.) It, I₁, I₂. 13, 14 C) THE INDIVIDUAL ACTIVE POWER D.) THE INDIVIDUAL E-) THE INDIVIRYAL 12 D 601 ↓ Is ZA= (90-j100) (80+;70) +30+; 60 = ANS (90-100 +80 tj 70) Z+= (ANS) (40-j50) + 10 - 120 (ANS+40-550) 8012 INDUCTIVE REACTIVE POWER 7002 = √14 902 100-2
V₁= Soo Lov ・IND: 9.7 Z₁ 102 H # #r 2052 £90 JIDO ) ( 80 + 1707 from Hoat •400 50.2 3002 2T = 73.422 -37.409⁰ ✓ n b.) It, I₁, I₂. 13, 14 C) THE INDIVIDUAL ACTIVE POWER D.) THE INDIVIDUAL E-) THE INDIVIRYAL 12 D 601 ↓ Is ZA= (90-j100) (80+;70) +30+; 60 = ANS (90-100 +80 tj 70) Z+= (ANS) (40-j50) + 10 - 120 (ANS+40-550) 8012 INDUCTIVE REACTIVE POWER 7002 = √14 902 100-2
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:R
O
U
15
T'
50
HY
ME
ST
P
Vr= Soo Lov
FIND:
9.7 Z₁
10
册
#r
£90 JIDO) ( 80 +1707
to-100*
2052
Reg
b.) It, I₁, I₂. 13, 14
C) THE INDIVIDUAL ACTIVE POWER
D. THE INDIVIDUAL
E-) THE
1
67 PHASE DIFFERENCE I P.f.
H) DRAW THE
1.1 709
zeq
ZA= (90-j100) (80+;70)
(90-100 +80 tj 70)
Z+= (ANS) (40-j50) + 10 - 120
(ANS+40-550)
2₁= 73.422 -37.409° ✓
400
50-12
F.) APPARENT POWER: S = V₁ Ir =
L
Req
)
INDUCTIVE REACTIVE POWER
INDIVIDUAL CAPACITIVE REACTIVE POWER
EQUIVALEPT SERIES
хед
and eq
3002
th
вол
+30+j60
V4 ²
2T
↓ Is
I7² z
CONNECTION
8022
7052
ZT
= ANS
↓ 14
902
100-2
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