v Part 4: Complete Response of a 2nd Order Circuit X Incorrect. You will need to find the current through the capacitor at t=0+ using the information provided. Note that the value of the voltage source at t=0 is simply 5 volts. Find v(t) for t>0 for the circuit shown in the figure when v(0)= 4 V and (0)=0. 10 12 5 Cos / V 0.5 H 1/12 Fv The complete response is the forded response plus the natural response v(t)=kze3+k4e4(+1.24*cos(t)+(-1.94*sin(t)); Find the coefficients kg and ka based on the initial conditions. 28.68 k3 = -25.92 k4= Click if you would like to Show Work for this question: Open Show Work

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter24: Resistive-inductive-capacitive Parallel Circuits
Section: Chapter Questions
Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...
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v Part 4: Complete Response of a 2nd Order Circuit
X Incorrect. You will need to find the current through the capacitor at t=0+ using the information provided. Note that the value of the voltage source at t=0 is simply 5
volts.
Find v(t) for t>0 for the circuit shown in the figure when v(0)= 4 V and (0)=0.
1Ω
10
5 Cos / V
0.5 H
1/12 Fv
The complete response is the forded response plus the natural response
v(t)=kze3 +k4e4 t+1.24*cos(t)+(-1.94*sin(t));
Find the coefficients kz and ka based on the initial conditions.
Ly
28.68
k3 =
-25.92
K4 =
Click
you would like to Show Work for this question: Open Show Work
Transcribed Image Text:v Part 4: Complete Response of a 2nd Order Circuit X Incorrect. You will need to find the current through the capacitor at t=0+ using the information provided. Note that the value of the voltage source at t=0 is simply 5 volts. Find v(t) for t>0 for the circuit shown in the figure when v(0)= 4 V and (0)=0. 1Ω 10 5 Cos / V 0.5 H 1/12 Fv The complete response is the forded response plus the natural response v(t)=kze3 +k4e4 t+1.24*cos(t)+(-1.94*sin(t)); Find the coefficients kz and ka based on the initial conditions. Ly 28.68 k3 = -25.92 K4 = Click you would like to Show Work for this question: Open Show Work
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