Initial Relative Saturation = 0.300: From the Antoine equation (Table B.4), the vapor pressure of carbon tetrachloride at 34°C is = 169 mm Hg. Consequently, * PCC₁₁ PCC14 yoP P = 760 mm Hg = = 0.300 = * 4 PCC₁₁ (34°C) 169 mm Hg yo 0.0667 mol CCl4/mol V = 50.0 L T = 34°C P = 1.00 atm n (mol) yo (mol CC14/mol) V = 50.0 L T = 34°C P = 1.00 atm n (mol) 0.001 mol CCl4/mol mc (g C) 0 g CC14 adsorbed mc (g C) mads (g CC14 adsorbed)
Initial Relative Saturation = 0.300: From the Antoine equation (Table B.4), the vapor pressure of carbon tetrachloride at 34°C is = 169 mm Hg. Consequently, * PCC₁₁ PCC14 yoP P = 760 mm Hg = = 0.300 = * 4 PCC₁₁ (34°C) 169 mm Hg yo 0.0667 mol CCl4/mol V = 50.0 L T = 34°C P = 1.00 atm n (mol) yo (mol CC14/mol) V = 50.0 L T = 34°C P = 1.00 atm n (mol) 0.001 mol CCl4/mol mc (g C) 0 g CC14 adsorbed mc (g C) mads (g CC14 adsorbed)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
A 50.0-liter tank contains an air–carbon tetrachloride mixture at 1 atm absolute, 34°C, and 30.0% relative saturation. 50 grams of activated carbon is placed in the tank to adsorb CCl4. The temperature of the tank contents is maintained at 34°C, and clean air is continuously supplied to the tank throughout the process to maintain the total pressure at 1.00 atm. Find the mole fraction remaining in the gas phase if only 50 grams of activated carbon is placed into the containe
Transcribed Image Text:Initial Relative Saturation = 0.300:
From the Antoine equation (Table B.4), the vapor pressure of carbon tetrachloride at 34°C is
= 169 mm Hg. Consequently,
*
PCC₁₁
PCC14
yoP
P =
760 mm Hg
=
= 0.300
=
*
4
PCC₁₁ (34°C)
169 mm Hg
yo 0.0667 mol CCl4/mol
Transcribed Image Text:V = 50.0 L
T = 34°C
P = 1.00 atm
n (mol)
yo (mol CC14/mol)
V = 50.0 L
T = 34°C
P = 1.00 atm
n (mol)
0.001 mol CCl4/mol
mc (g C)
0 g CC14 adsorbed
mc (g C)
mads (g CC14 adsorbed)
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