QUESTION 3 100 kg/s of solution containing 28 mass% CuSO4 is cooled slowly to 10°C to form crystals of CuSO4*5H2O. The solubility of CuSO4 at 10°C is 9.9 kg/ 100 kg water. It is estimated that 4% of the water entering the crystallizer is lost by evaporation. 3.1. Draw a diagram of the crystallizer showing all streams around it and use the yield method to calculate mass of crystals produced in the crystallizer. Additional information: Cu= 63.5 g/mol, H= 1 g/mol, S= 32 g/mol, O= 16 g/mol

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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QUESTION 3
100 kg/s of solution containing 28 mass% CuSO4 is cooled slowly to 10°C to form
crystals of CuSO4*5H2O. The solubility of CuSO4 at 10°C is 9.9 kg/ 100 kg water. It is
estimated that 4% of the water entering the crystallizer is lost by evaporation.
3.1. Draw a diagram of the crystallizer showing all streams around it and use the
yield method to calculate mass of crystals produced in the crystallizer.
Additional information: Cu= 63.5 g/mol, H= 1 g/mol, S= 32 g/mol, O= 16 g/mol
Transcribed Image Text:QUESTION 3 100 kg/s of solution containing 28 mass% CuSO4 is cooled slowly to 10°C to form crystals of CuSO4*5H2O. The solubility of CuSO4 at 10°C is 9.9 kg/ 100 kg water. It is estimated that 4% of the water entering the crystallizer is lost by evaporation. 3.1. Draw a diagram of the crystallizer showing all streams around it and use the yield method to calculate mass of crystals produced in the crystallizer. Additional information: Cu= 63.5 g/mol, H= 1 g/mol, S= 32 g/mol, O= 16 g/mol
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