A particle moves in one-dimensional motion through a field for which the potential energy of the particle–field system is U(x) = (A)/(x3) - (B)/(x)where A = 0.150 eV ⋅ nm3 and B = 3.68 eV ⋅ nm. The shape of this function is shown. (a) Find the equilibrium position x0 of the particle. (b) Determine the depth U0 of this potential well. (c) In moving along the x axis, what maximum force toward the negative x direction does the particle experience? UtotalUoFigure P42.41 Problems 41 and 42.

given quantities: U(x)=(A)/(x3) -B/x A=0.15 B=3.68 (a) To find the equilibrium position , first ,…

Answered: Utotal Uo Figure P42.41 Problems 41 and…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A particle moves in one-dimensional motion through a field for which the potential energy of the particle–field system is
U(x) = (A)/(x³) - (B)/(x)
where A = 0.150 eV ⋅ nm³ and B = 3.68 eV ⋅ nm. The shape of this function is shown. (a) Find the equilibrium position x₀ of the particle. (b) Determine the depth U₀ of this potential well. (c) In moving along the x axis, what maximum force toward the negative x direction does the particle experience?

Utotal
Uo
Figure P42.41 Problems 41 and 42.

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