Using the table of the weak base below, you have chosen Ethylamine as your weak base in the buffer solution. You have already added enough of the conjugate acid salt to make the buffer solution concentration at 0.52 M in this salt. The desired pH of the buffer should be equal to 10.1. Values of K, for Some Common Weak Bases Conjugate Name Formula Acid Ammonia Methylamine Ethylamine NH, CH NH," CH&NH, CH,NH," CH NH 1.8 x 10- 4.38 x 10- 5.6 x 10 3.8 x 10-10 1.7 x 10- NH, CH NH; CH NH, CH,NH, C,H.N Aniline Pyridine 3. Compute the concentration of the weak base in Molarity. (round off final answer to 4 decimal places)
Using the table of the weak base below, you have chosen Ethylamine as your weak base in the buffer solution. You have already added enough of the conjugate acid salt to make the buffer solution concentration at 0.52 M in this salt. The desired pH of the buffer should be equal to 10.1. Values of K, for Some Common Weak Bases Conjugate Name Formula Acid Ammonia Methylamine Ethylamine NH, CH NH," CH&NH, CH,NH," CH NH 1.8 x 10- 4.38 x 10- 5.6 x 10 3.8 x 10-10 1.7 x 10- NH, CH NH; CH NH, CH,NH, C,H.N Aniline Pyridine 3. Compute the concentration of the weak base in Molarity. (round off final answer to 4 decimal places)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the table of the weak base below, you have chosen Ethylamine as your weak base in the buffer solution. You have already added enough of the conjugate acid salt to make the buffer
solution concentration at 0.52 M in this salt. The desired pH of the buffer should be equal to 10.1.
Values of K, for Some Common Weak Bases
Conjugate
Acid
Name
Formula
1.8 x 10 5
4.38 × 10-4
NH,
CH;NH;*
CH;NH3
CH;NH;+
C;H;NH*
Ammonia
Methylamine
Ethylamine
Aniline
NH3
CH;NH,
CH;NH2
C,H;NH,
C;H;N
5.6 x 10-4
3.8 х 10-10
Pyridine
1.7 x 10-9
3. Compute the concentration of the weak base in Molarity.
(round off final answer to 4 decimal places)
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