A 10.0 mL solution of 0.540 M NH, is titrated with a 0.180 M HCl solution. Calculate the pH after the following additions of the HCI solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits. Note: Reference the K of acids at 25 °C and K, of bases at 25 °C tables for additional information. Part 1 of 4 0.00 mL Added, pH = Part 2 of 4 10.0 mL Added, pH = Part 3 of 4 30.0 mL Added, pH = Part 4 of 4 40.0 mL Added, pH = X X 5 X

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A 10.0 mL solution of 0.540 M NH, is titrated with a 0.180 M HCl solution. Calculate the pH after the following additions of the HCI solution: 0.00 mL,
10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits.
Note: Reference the K of acids at 25 °C and K, of bases at 25 °C tables for additional information.
Part 1 of 4
0.00 mL Added, pH =
Part 2 of 4
10.0 mL Added, pH =
Part 3 of 4
30.0 mL Added, pH =
Part 4 of 4
40.0 mL Added, pH =
X
X
5
X
Transcribed Image Text:A 10.0 mL solution of 0.540 M NH, is titrated with a 0.180 M HCl solution. Calculate the pH after the following additions of the HCI solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Be sure your answer has the correct number of significant digits. Note: Reference the K of acids at 25 °C and K, of bases at 25 °C tables for additional information. Part 1 of 4 0.00 mL Added, pH = Part 2 of 4 10.0 mL Added, pH = Part 3 of 4 30.0 mL Added, pH = Part 4 of 4 40.0 mL Added, pH = X X 5 X
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