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Using the graph for the inelastic collision shown above, calculate the absolute value of the change of rotational kinetic energy (in J) from just before to just after the collision. Use the moment of inertia that is calculated from the mass and radius of the disc(s) (like you did in Q1). Round your answer to 4 decimal places. NB. AK = | Kf- K;| Your Answer: Answer

Using the graph for the inelastic collision shown above, calculate the absolute value of the change of rotational kinetic energy (in J) from just before to just after the collision. Use the moment of inertia that is calculated from the mass and radius of the disc(s) (like you did in Q1). Round your answer to 4 decimal places. NB. AK = | Kf- K;| Your Answer: Answer

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Using the graph for the inelastic collision shown above, calculate the absolute value of the change of rotational kinetic energy (in J) from just before to just after the collision. Use the moment of inertia that is calculated from the mass and radius of the disc(s) (like you did in Q1). Round your answer to 4 decimal places. NB. AK = | Kf- K;| Your Answer: Answer Saved Using the graph for the inelastic collision shown above, what is the absolute value of the rate of decrease of the speed of the system (in rad/s2) after the collision? Round your answer to the same precision as you see in the graph. Your Answer:
Transcribed Image Text:Using the graph for the inelastic collision shown above, calculate the absolute value of the change of rotational kinetic energy (in J) from just before to just after the collision. Use the moment of inertia that is calculated from the mass and radius of the disc(s) (like you did in Q1). Round your answer to 4 decimal places. NB. AK = | Kf- K;| Your Answer: Answer Saved Using the graph for the inelastic collision shown above, what is the absolute value of the rate of decrease of the speed of the system (in rad/s2) after the collision? Round your answer to the same precision as you see in the graph. Your Answer:
Q6 to Q10 are based on the following graph that shows the angular velocity as a function of time for an inelastic collision between two discs, similar to the collision done in Part 2 of your lab. Inelastic collision 50- 40- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.5269 rad/s/s b (Y-Intercept): 47.10 rad/s Correlation: -0.9983 RMSE: 0.06649 rad/s Statistics for: Data Set |Ang. velocity min: 20.81 at 10.69 max: 41.91 at 9.963 30- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.2070 rad/s/s b (Y-Intercept): 22.88 rad/s Correlation: -0.9744 RMSE: 0.1089 rad/s 20- 10- 10 15 20 (5.72, 19.03) (At:22.00 Ay:0.00) Time (s) Ang. velocity (rad/s)
Transcribed Image Text:Q6 to Q10 are based on the following graph that shows the angular velocity as a function of time for an inelastic collision between two discs, similar to the collision done in Part 2 of your lab. Inelastic collision 50- 40- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.5269 rad/s/s b (Y-Intercept): 47.10 rad/s Correlation: -0.9983 RMSE: 0.06649 rad/s Statistics for: Data Set |Ang. velocity min: 20.81 at 10.69 max: 41.91 at 9.963 30- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.2070 rad/s/s b (Y-Intercept): 22.88 rad/s Correlation: -0.9744 RMSE: 0.1089 rad/s 20- 10- 10 15 20 (5.72, 19.03) (At:22.00 Ay:0.00) Time (s) Ang. velocity (rad/s)
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