Using the end-group analysis to find molecular weight, 6 mol of 1,4-butanediamine reacted with 6 mol 1,6-hexane-diacid (see formulas below). After the reaction titration was performed using Mg(OH)2 (which reacts with-COOH group only) to determine the number of acid groups remaining free after the polymerization. If 15 ml of 0.5M Mg(OH)z were required to neutralize the polymer, what is the average number average molecular weight (M,) of the polymer. 1,2-butanediamine: H2N - CH2 - CH2 – CH2 – CH2 – NH2 1,6-hexane-diacid: HOOC – CH2 – CH2 - CH2 – CH2 – COOH

Using the end-group analysis to find molecular weight, 6 mol of 1,4-butanediamine reacted with 6 mol 1,6-hexane-diacid (see formulas below). After the reaction titration was performed using Mg(OH)2 (which reacts with-COOH group only) to determine the number of acid groups remaining free after the polymerization. If 15 ml of 0.5M Mg(OH)z were required to neutralize the polymer, what is the average number average molecular weight (M,) of the polymer. 1,2-butanediamine: H2N - CH2 - CH2 – CH2 – CH2 – NH2 1,6-hexane-diacid: HOOC – CH2 – CH2 - CH2 – CH2 – COOH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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