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0.155 g of Acyclovir cream was mixed with 50 mL of 0.5M Sulphuric acid and extracted with 50 mL of ethyl acetate. The lower aqueous layer was collectedand the organic layer extracted with an additional 20 mL of 50mL of sulphuric acid. The aqueous layers were combined and made up to 100 mL with sulphuric acid. A portion of The resulting solution was filtered and 10 mL of the filtrate was further diluted to 50 mL. The absorbance of the final diluted solution was 0.833 at a wavelength of 255 nm. Additional information: A(1%, 1 cm) value for acyclovir at 255 nm = 562.

0.155 g of Acyclovir cream was mixed with 50 mL of 0.5M Sulphuric acid and extracted with 50 mL of ethyl acetate. The lower aqueous layer was collectedand the organic layer extracted with an additional 20 mL of 50mL of sulphuric acid. The aqueous layers were combined and made up to 100 mL with sulphuric acid. A portion of The resulting solution was filtered and 10 mL of the filtrate was further diluted to 50 mL. The absorbance of the final diluted solution was 0.833 at a wavelength of 255 nm. Additional information: A(1%, 1 cm) value for acyclovir at 255 nm = 562.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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0.155 g of Acyclovir cream was mixed with 50 mL of 0.5M Sulphuric acid and extracted with 50 mL of ethyl acetate. The lower aqueous layer was collectedand the organic layer extracted with an additional 20 mL of 50mL of sulphuric acid. The aqueous layers were combined and made up to 100 mL with sulphuric acid. A portion of The resulting solution was filtered and 10 mL of the filtrate was further diluted to 50 mL. The absorbance of the final diluted solution was 0.833 at a wavelength of 255 nm. Additional information: A(1%, 1 cm) value for acyclovir at 255 nm = 562.
Transcribed Image Text:0.155 g of Acyclovir cream was mixed with 50 mL of 0.5M Sulphuric acid and extracted with 50 mL of ethyl acetate. The lower aqueous layer was collectedand the organic layer extracted with an additional 20 mL of 50mL of sulphuric acid. The aqueous layers were combined and made up to 100 mL with sulphuric acid. A portion of The resulting solution was filtered and 10 mL of the filtrate was further diluted to 50 mL. The absorbance of the final diluted solution was 0.833 at a wavelength of 255 nm. Additional information: A(1%, 1 cm) value for acyclovir at 255 nm = 562.
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