Using the data from the Trials with Graduated Cylinder (Trial 1) divide the mass recorded by the volume of H2O. Show the work and be sure to use units and the appropriate significant figures.  What is the answer?  Explain why this is not the density of water!   109.82g/10.49mL = 10.47 g/mL         From the equation: m = DV the intercept value appears to be zero, which makes sense because if there is no volume, the mass of the liquid will be zero.  Look at graph 2 (Buret) and determine the "y inter­cept" both visually and mathematically.  Use proper units for both values listed.          Visual intercept Not possible (if possible; if not possible put Not Possible on line)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. Using the data from the Trials with Graduated Cylinder (Trial 1) divide the mass recorded by the volume of H2O. Show the work and be sure to use units and the appropriate significant figures.  What is the answer?  Explain why this is not the density of water!

 

109.82g/10.49mL = 10.47 g/mL

 

 

 

 

  1. From the equation: m = DV the intercept value appears to be zero, which makes sense because if there is no volume, the mass of the liquid will be zero.  Look at graph 2 (Buret) and determine the "y inter­cept" both visually and mathematically.  Use proper units for both values listed.

        

Visual intercept

Not possible

(if possible; if not possible put Not Possible on line)

 

Mathematical intercept: (from the equation of the line)

 

               (You can consult the lab manual for information about the intercept or check with the instructor)

 

     Why is this value not zero and what does this value represent in the real, physical world?

Buret
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R? = 0.9894...
%3D
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Volume (mL)
Mass (g)
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Transcribed Image Text:Buret 180 160 R? = 0.9894... %3D 140 120 100 80 60 40 20 10 30 40 50 60 Volume (mL) Mass (g) 20
Graduated Cylinder
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R? = 0.6142
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Transcribed Image Text:Graduated Cylinder 180 160 140 120 100 80 60 40 R? = 0.6142 20 5 10 15 20 25 30 35 40 45 Volume (mL) Mass (g)
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