USING THE COMPONENT METHOD, SOLVE THE FOLLOWING: Four forces acting on a bolt A as shown, determine the magnitude and the direction of the resultant. F = 150 N F; = 115 N 12 40 55 F3 = 95 N 25 F= 130 N
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- What is the force of static friction between the top and bottom blocks assuming the surface is frictionless and the surface between top and bottom blocks has no slipping?A beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (b) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = (c) Check the answer to part (e) by computing torques around the first pivot point.x = (d)Except for possible slight differences due to rounding, is the answer the same for F and E?Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please
- The uniform seesaw shown below is balanced on a fulcrum located d1 = 3.5m from the left end. The bigger boy on the left end has a mass m1 =75 kg. The smaller boy on the right end has a mass of m2 = 55 kg and is a distance d2 = 4.5 m from the fulcrum. The mass of the board is mb. Draw all forces acting on the seesaw board showing their directions and locations. Where would you draw the weight of the board? Identify and show the direction of rotations caused by the torques provided by all forces about the fulcrum. If the seesaw is in static equilibrium, write down the two conditions of static equilibrium symbolically using the forces and distances in the figure. Solve for the mass of the board. Calculate the force of fulcrum on the board.Hand written and clean answerA rider of mass 77.0-kg sits 1.60 meters left of the pivot point. A different rider sits 3.3 meters to the right of the pivot point. If the see-saw is in equilibrium, what is the rider on the right's mass? The mass of the see-saw is 18.9-kg Give your answer in kilograms to 3 significant figures (1 decimal place).
- A beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n₁ on the beam, and the second pivot placed a distance = 4.00 m from the left end exerts a normal force n₂. A woman of mass m = 61.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. m L M (a) Sketch a free-body diagram, labeling the gravitational and normal forces acting on the beam and placing the woman x meters to the right of the first pivot, which is the origin. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet. (b) Where is the woman when the normal force ₁ is the greatest? X = m (c) What is n₁ when the beam is about to tip? N (d) Use the force equation of equilibrium to find the value of n₂ when the beam is about to tip. N (e) Using the result of part (c) and the torque equilibrium…A rider of mass 78.0-kg sits 1.70 meters left of the pivot point. A different rider sits 3.5 meters to the right of the pivot point. If the see-saw is in equilibrium, what is the rider on the right's mass? The mass of the see-saw is 19.2-kg Give your answer in kilograms to the correct number of significant figures.A beam resting on two pivots has a length of L = 6.00 m and mass M = 94.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 51.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a)Where is the woman when the normal force n1 is the greatest? x = _____m(b) What is n1 when the beam is about to tip?____N(c) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip.____N