**Seesaw Balance Experiment for Educational Purpose****Objective:**Understanding the conditions for equilibrium in a seesaw system with negligible mass using the principles of torque and force balance.**Description of the Setup and Figure Analysis:**In the illustrated setup, two children are balanced on a seesaw.1. **Children's Positions and Masses:** - The first child (mass \( m_1 = 27.2 \) kg) sits \( 1.24 \) meters from the pivot point (denoted by \( r_1 \)). - The second child (mass \( m_2 = 35 \) kg) sits \( 1.00 \) meter from the pivot point (denoted by \( r_2 \)).2. **Forces Acting on the System:** - The weights of the children exert downward forces (\( W_1 \) and \( W_2 \)): - \( W_1 \) = \( m_1 \cdot g \) (gravity's effect on the first child's mass) - \( W_2 \) = \( m_2 \cdot g \) (gravity's effect on the second child's mass) - \( F_p \) is the supporting force exerted by the pivot, which acts upwards to balance the seesaw system.**Conditions for Equilibrium:**To ensure the seesaw remains in equilibrium (net torque is zero), the torques caused by the weights of both children relative to the pivot must be equal and opposite:\[ W_1 \cdot r_1 = W_2 \cdot r_2 \]**Steps to Calculate Supporting Force (\(F_p\)):**1. **Calculate the weights:** - \( W_1 = 27.2 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \) - \( W_2 = 35 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \)2. **Apply torque equilibrium condition:** - Substitute values into the equation \( W_1 \cdot r_1 = W_2 \cdot r_2 \) - Simplify to find if torques are balanced.3. **Calculate the Supporting Force (\( F_p \)):** - The sum

It is give that both the children are balanced state (as net torque is zero) so net force will be…

Answered: The two children shown in the figure…

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