For the stepladder shown in the figure, sides AC and CE are each 3.31 m long and hinged at C. Bar BD is a tie-rod 0.819 m long, halfwayup. A man weighing 948 N climbs 2.48 m along the ladder. Assuming that the floor is frictionless and neglecting the mass of the ladder,fınd (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor at (b) A and (c) E. (Hint: Isolate parts ofthe ladder in applying the equilibrium conditions.)BE(a) NumberiUnits(b) NumberiUnits(c) NumberiUnits>

It is given in the figure that is AC and CE is equal 3.31 m BD is 0.819m Weight of man is 948 Newton and he is standing at 2.48m We have to find tension and magnitude of forces about A and E free body diagram for the left side of ladder is given below Free body diagram of right side of ladder is given below By solving above equations we get T= 3W tanθ / 4 From diagram θ = cos-1(.819/3.31 ) = 75.67° A) T= 3× 948× tan75.67° /4 = 2783.3 N C) FE= 5447.68 N B) FA= W- FE = 948 - 5447.68 |FA|= 4499.69

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For the stepladder shown in the figure, sides AC and CE are each 3.31 m long and hinged at C. Bar BD is a tie-rod 0.819 m long, halfway up. A man weighing 948 N climbs 2.48 m along the ladder. Assuming that the floor is frictionless and neglecting the mass of the ladder, find (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor at (b) A and (c) E. (Hint: Isolate parts of the ladder in applying the equilibrium conditions.)

For the stepladder shown in the figure, sides AC and CE are each 3.31 m long and hinged at C. Bar BD is a tie-rod 0.819 m long, halfway up. A man weighing 948 N climbs 2.48 m along the ladder. Assuming that the floor is frictionless and neglecting the mass of the ladder, find (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor at (b) A and (c) E. (Hint: Isolate parts of the ladder in applying the equilibrium conditions.)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Rotational Equilibrium And Rotational Dynamics

In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.

Equilibrium of Forces

The tension created on one body during push or pull is known as force.

Question

For the stepladder shown in the figure, sides AC and CE are each 3.31 m long and hinged at C. Bar BD is a tie-rod 0.819 m long, halfway
up. A man weighing 948 N climbs 2.48 m along the ladder. Assuming that the floor is frictionless and neglecting the mass of the ladder,
fınd (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor at (b) A and (c) E. (Hint: Isolate parts of
the ladder in applying the equilibrium conditions.)
B
E
(a) Number
i
Units
(b) Number
i
Units
(c) Number
i
Units
>

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