Using the celsius_to_kelvin function as a guide, create a new function, change the name to kelvin_to_celsius, and modify the function accordingly. Sample output with input: 283.1510.0 C is 283.15 K 283.15 K is 10.0 C def celsius_to_kelvin(value_celsius): value_kelvin = 0.0 value_kelvin = value_celsius + 273.15 return value_kelvin INSERT CODE value_c = 10.0 print(value_c, 'C is', celsius_to_kelvin(value_c), 'K') value_k = float(input()) print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')
Using the celsius_to_kelvin function as a guide, create a new function, change the name to kelvin_to_celsius, and modify the function accordingly. Sample output with input: 283.1510.0 C is 283.15 K 283.15 K is 10.0 C def celsius_to_kelvin(value_celsius): value_kelvin = 0.0 value_kelvin = value_celsius + 273.15 return value_kelvin INSERT CODE value_c = 10.0 print(value_c, 'C is', celsius_to_kelvin(value_c), 'K') value_k = float(input()) print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Using the celsius_to_kelvin function as a guide, create a new function, change the name to kelvin_to_celsius, and modify the function accordingly.
Sample output with input:
283.1510.0 C is 283.15 K 283.15 K is 10.0 C
def celsius_to_kelvin(value_celsius):
value_kelvin = 0.0
value_kelvin = value_celsius + 273.15
return value_kelvin
INSERT CODE
value_c = 10.0
print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')
value_k = float(input())
print(value_k, 'K is', kelvin_to_celsius(value_k), 'C')
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