Using Kirchhoff's rules, find the following. (E, = 70.9 V, Ɛ, = 61.7 V, and ɛ, = 78.1 V.)4.00 kNE,R.R,S 3.00 kN2.00 kNR1(a) the current in each resistor shown in the figure above(b) the potential difference between points c and fStep 1We assume the currents in the three branches of this circuit are directed as shown in the diagram below.4.00 k2R3R23.00 k.2.00 k2fR1If our assumed directions for the currents are correct, the calculated currents will have positive signs.We apply Kirchhoff's junction rule at point c to obtainI2 = I1 + I3.[1]We apply Kirchhoff's loop rule, going clockwise around loop abcfa to obtainE, - E2 - R2I2 - R¿l1 = 0.Solving for I,, we haveE, - E, - R2 - () -).I =R1so4 = (C10-3 A) - (O )2: (2)Applying Kirchhoff's loop rule, going counterclockwise around loop edcfe, we haveEz - R3l3 - E2 - R2I2 = 0.Solving for Ia, we have8,- E, - Rzlz - ()·I3 =R3soIz =J- 10-A) - (CSubmitSkip (you cannot come back)

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Using Kirchhoff's rules, find the following. (E, = 70.9 V, E, = 61.7 V, and E, = 78.1 V.) 4.00 kN R 3.00 kM 2.00 kN R1 (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f

Using Kirchhoff's rules, find the following. (E, = 70.9 V, E, = 61.7 V, and E, = 78.1 V.) 4.00 kN R 3.00 kM 2.00 kN R1 (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

Using Kirchhoff's rules, find the following. (E, = 70.9 V, Ɛ, = 61.7 V, and ɛ, = 78.1 V.)
4.00 kN
E,
R.
R,S 3.00 kN
2.00 kN
R1
(a) the current in each resistor shown in the figure above
(b) the potential difference between points c and f
Step 1
We assume the currents in the three branches of this circuit are directed as shown in the diagram below.
4.00 k2
R3
R23.00 k.
2.00 k2
f
R1
If our assumed directions for the currents are correct, the calculated currents will have positive signs.
We apply Kirchhoff's junction rule at point c to obtain
I2 = I1 + I3.
[1]
We apply Kirchhoff's loop rule, going clockwise around loop abcfa to obtain
E, - E2 - R2I2 - R¿l1 = 0.
Solving for I,, we have
E, - E, - R2 - () -).
I =
R1
so
4 = (C
10-3 A) - (O )2: (2)
Applying Kirchhoff's loop rule, going counterclockwise around loop edcfe, we have
Ez - R3l3 - E2 - R2I2 = 0.
Solving for Ia, we have
8,- E, - Rzlz - ()·
I3 =
R3
so
Iz =
J- 10-A) - (C
Submit
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