Using Kirchhoff's rules, find the following. (₁ = 70.7 V, ₂ = 60.9 V, and 3 = 78.7 V.)4.00 knwwwR₂baE₁So2.00 knwwR₁1₁soStep 1We assume the currents in the three branches of this circuit are directed as shown in the diagram below.4.00 ΚΩdwwR3(a) the current in each resistor shown in the figure above(b) the potential difference between points c and fa12C2.00 ΚΩwwR₁If our assumed directions for the currents are correct, the calculated currents will have positive signs.Solving for I, we haveE₂R₂2 3.00 ΚΩWe apply Kirchhoff's junction rule at point c to obtain1₂ = 1₁ + 13.[1]R2 € 3.00 ΚΩWe apply Kirchhoff's loop rule, going clockwise around loop abcfa to obtainE₁-E₂-R₂I₂R₁1₁ = 0.dEsSolving for I, we have]) = 4£₁ — &z - Ryb2 = (²₁ —-€²) - (22²) ¹2R₁1₁ = 5.1xx10-3A)-([[2]Applying Kirchhoff's loop rule, going counterclockwise around loop edcfe, we haveE3-R313-₂-R₂I₂ = = 0.´ E, - E2 - Ryb₂ = (B₁ −³2) - (223)³²13 =R3x10-³ A)-(C²₂. [3]

Answered: Image /qna-images/answer/016edc9a-9bcd-4fa6-bd7e-34184c445641.jpg

Using Kirchhoff's rules, find the following. (₁ = 70.7 V, ₂ = 60.9 V, and 3 = 78.7 V.) 4.00 kn www R₂ Step 1 b a E₁ 2.00 kn ww R₁ C E₂ R₂2 13.00 ΚΩ d Es (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f

Using Kirchhoff's rules, find the following. (₁ = 70.7 V, ₂ = 60.9 V, and 3 = 78.7 V.) 4.00 kn www R₂ Step 1 b a E₁ 2.00 kn ww R₁ C E₂ R₂2 13.00 ΚΩ d Es (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Resistivity

Resistivity is a characteristic property of the conductor’s material that measures the extent to which the material opposes the flow of current. It is denoted by the Greek letter “rho”. Electrical resistivity, also known as specific resistance, depends on the nature of the material of the conductor and is unaffected by its dimensions.

Question

Using Kirchhoff's rules, find the following. (₁ = 70.7 V, ₂ = 60.9 V, and 3 = 78.7 V.)
4.00 kn
www
R₂
b
a
E₁
So
2.00 kn
ww
R₁
1₁
so
Step 1
We assume the currents in the three branches of this circuit are directed as shown in the diagram below.
4.00 ΚΩ
d
ww
R3
(a) the current in each resistor shown in the figure above
(b) the potential difference between points c and f
a
12
C
2.00 ΚΩ
ww
R₁
If our assumed directions for the currents are correct, the calculated currents will have positive signs.
Solving for I, we have
E₂
R₂2 3.00 ΚΩ
We apply Kirchhoff's junction rule at point c to obtain
1₂ = 1₁ + 13.
[1]
R2 € 3.00 ΚΩ
We apply Kirchhoff's loop rule, going clockwise around loop abcfa to obtain
E₁-E₂-R₂I₂R₁1₁ = 0.
d
Es
Solving for I, we have
]) = 4
£₁ — &z - Ryb2 = (²₁ —-€²) - (22²) ¹2
R₁
1₁ = 5.1
xx10-3A)-([
[2]
Applying Kirchhoff's loop rule, going counterclockwise around loop edcfe, we have
E3-R313-₂-R₂I₂ = = 0.
´ E, - E2 - Ryb₂ = (B₁ −³2) - (223)³²
13 =
R3
x
10-³ A)-(C
²₂. [3]

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