Three resistors R, - 85.0 2, R, = 22.9 2, R, = 70.0 2, and two batteries E, = 40.0 V, and E, = 357 V are connected as shown in the diagram below. R1 R2 (a) What current flows through R, R2, and R,? 1 = 12 = 1 = A A A (b) What is the absolute value of the potential difference across R,, R2, and R,? JAVRIl - JAVR21 = JAVR31 = V ww ww
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Use the Kirchhoff's law to calculate the currents,
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- Two batteries with emf &₁ and E2, with internal resistances ₁ and ₂ respectively, are connected as shown in the diagram below. (Assume ₁ = 12 V and r₁=1 N.) | www (a) Calculate the magnitude and indicate the direction of flow of current in the figure shown above. E₂ = 33.0 V and r₂ = 0.65 0. 60 X What is the net voltage when the two batteries are connected in opposition to each other? What is the net internal resistance of this circuit? A counterclockwise magnitude direction (b) Find the terminal voltage of each battery. V₁ = 48 X What is the sign of the current if it is flowing into the positive terminal of the battery? V V₂ = 6 X What is the sign of the current if it is flowing into the positive terminal of the battery? VA 22 Ω resistor and a 4 Ω resistor are connected in series to an ideal 12 V battery.Find the current in each resistor.Answer in units of A.Find the potential difference across the firstresistor.Answer in units of V.Find the potential difference across the secondresistor.Answer in units of V.2. In Figure 2 the ideal batteries have emfs E = 150 V and E, = 50 V and the resistances are %3D R1 = 3.0 N and R2 = 2.0 N. If the potential at P is 100 V, what is it at Q? R P Figure 2
- Find the current through and the voltage across resistor R.. The values of the resistors are: R, = 4.0 2, R, =2.0 2, R, = 6.0 2, R =3.0 2. %3D R2 V, = 12 V www R. www R, V, = 6.0 V www www R,X N 3) Consider a cube whose center is at the origin, and all edges of the cube are 4 cm. A battery (DC voltage) with voltage of Vo is connected to bottom and top faces (sides) of cube as shown in left figure. a) If the volume current density in cube is given as; J=100 V₁ (x² + y²)â. A/m² then find the (DC) resistance of the structure. Hint: You can get the result without considering below part (part b). O= b) By assuming that electric field intensity is zero outside the cube (although practically there is nonzero electric field outside the cube, assume that this electric field is very small), if the conductivity of the material of the cube is given as; x² 1+ Z 0.02 10-2 S m then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take cube material's relative permittivity (dielectric constant) as &r = 1.Number 2. Show the step please.