The side effects of a new drug are being tested against a placebo. A simple randomsample of 565 patients yields the results below. At a significance level of a = 0.05, isthere enough evidence to conclude that the treatment is independent of the sideeffect of nausea?ResultDrug Placebo TOTALNausea361349No nausea 254262516TOTAL290275565Question 11 (1 point)What are correct the hypotheses?Ho: Treatment is independent of the side effects of nausea.H: Treatment is dependent of the side effects of nausea.O Ho: Treatment is dependent of the side effects of nausea.H: Treatment is independent of the side effects of nausea. Question 12 (1 point)Using Excel calculations, which of the following is a true statement?The p-value is 0.001175.The p-value is 0.05.The p-value cannot be determined by MS Excel methods.The p-value is 0.01175.Question 13 (1 point)By comparing a and the p-value, what is the correct decision?Reject the null hypothesis.ODo not reject the null hypothesis.

Q- 11) On the basis of the given Data : Formulating Hypothesis : H0 : Treatment is independent of…

Using Excel calculations, which of the following is a true statement? O The p-value is 0.001175. O The p-value is 0.05. The p-value cannot be determined by MS Excel methods. O The p-value is 0.01175. Question 13 (1 point) By comparing a and the p-value, what is the correct decision? OReject the null hypothesis. Do not reject the null hypothesis.

Using Excel calculations, which of the following is a true statement? O The p-value is 0.001175. O The p-value is 0.05. The p-value cannot be determined by MS Excel methods. O The p-value is 0.01175. Question 13 (1 point) By comparing a and the p-value, what is the correct decision? OReject the null hypothesis. Do not reject the null hypothesis.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Let p denote the population proportion of all buttered toast that will land with the buttered side down when dropped. Identify the null and alternative hypotheses to test the claim that buttered toast will land with the buttered side down 50% of the time. Ho p = H₁p 0.5 0.5 (Type integers or decimals. Do not round.) Identify the test statistic. z = -1.81 (Round to two decimal places as needed.) Identify the P-value. P-value = 0.070 (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that buttered toast will land with the buttered side down 50% of the time. Write a conclusion that addresses the test that the toast will land with the buttered side down more than 50% of the time. The intent of the experiment was to test Ho: p = down more than 50% of the time. 0.5 and H₁: p > 0.5.…
How to solve it on TI-84 Plus CE and Excel?
According to the Centers for Disease Control and Prevention, 10.5% of high school students currently use electronic cigarettes. A high sch the use of e-cigs at her school is higher. Complete parts (a) through (c) below (a) Dotermine the null and alternative hypotheses. Ho H (Type integers or decimals Do not round)
Solve question a,b and c please
Determine whether the claim stated below represents the null hypothesis or the alternative hypothesis. If a hypothesis test is performed, how should you interpret a decision that (a) rejects the null hypothesis or (b) fails to reject the null hypothesis? A scientist claims that the mean incubation period for the eggs of a species of bird is at least 34 days. Does the claim represent the null hypothesis or the alternative hypothesis? Since the claim a statement of equality, it represents the V hypothesis.
A report states the average temperature for the month of June on a specific tropical island is 98 degrees F. A meteorologist claims the report is not correct.. Data collected from 35 areas on the island showed an average temperature of 94 degrees F. Thepopulation standarddeviation is known to be 6.0 degrees F. At alpha = 0.05, can the report's average be rejected? For multiple choice question #1, tell what type of test: right-tailed, left-tailed, or two-tailed.
Using the accompanying New Account Processing data, perform chi-square tests for independence to determine if certification is independent of gender and if certification is independent of having prior industry background. Click the icon to view the New Account Processing data. - x Find the hypotheses for the chi-square test for independence to determine if certification is independent of gender. H: Certification and Gender are independent New Account Processing Data H₁ Certification and Gender are dependent Perform the chi-square test for independence to determine if certification is independent of gender. Compute the chi-square statistic. (Type an integer or decimal rounded to two decimal places as needed.) Gender Certified Prior Background M Y F Y Y M Y N N Y M F N Y Y Y Y Y Y N N F N Y M Y N M Y N F N Y N N F N Y M Y Y M N Y M N N M N Y Print Done
A researcher rejected the null where r(56) = .050, p = .27. Was the researcher correct in rejecting the null? Group of answer choices Yes No
In a one-tail hypothesis test where you reject H0 only in the lower tail, it was found that the p-value is 0.1469 if ZSTAT=−1.05. What is your statistical decision if you test the null hypothesis at the 0.05 level of significance? Question content area bottom Part 1 Choose the correct answer below. A. Reject the null hypothesis because the p-value is less than the level of significance. B. Reject the null hypothesis because the p-value is greater than the level of significance. C. Fail to reject the null hypothesis because the p-value is greater than the level of significance. D. Fail to reject the null hypothesis because the p-value is less than the level of significance.
For a hypothesis test of the claim that the mean amount of sleep for adults is less than 7 hours, technology output shows that the hypothesis test has power of 0.4033 of supporting the claim that u<7 hours of sleep when the actual population mean is 5.5 hours of sleep. Interpret this value of the power, then identify the value of B and interpret that value. Interpret this value of the power. O A. The chance of failing to recognize that =5.5 hours is not very high when in reality u= 5.5 hours. O B. The chance of failing to recognize that p<7 hours is not very high when in reality u=5.5 hours. O C. The chance of recognizing that u<7 hours is very high when in reality p = 5.5 hours. D. The chance of recognizing that u<7 hours is not very high when in reality u=5.5 hours. Identify the value of B and interpret that value. Select the correct choice below and fill in the answer box to complete your choice. (Round to four decimal places as needed.) O A. The value B= indicates that there is a…
Help with 13 and 14 please