Dose there is a claim that a certain population has a mean, μ, that is different than 6. You want to test this claim. To do so, you canple from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothnative hypothesis, H₁, as follows.Ho: μ=6H₁: μ#6ppose you also know the following information.The value of the test statistic based on the sample is -1.745 (rounded to 3 decimal places).The p-value is 0.081 (rounded to 3 decimal places).(a) Complete the steps below for this hypothesis test.Standard Normal DistributionStep 1: Select one-tailed or two-tailed.O One-tailedO Two-tailedStep 2: Enter the test statistic.(Round to 3 decimal places.)-1.745Step 3: Shade the area represented bythe p-value.ExplanationCheckⒸ2022 McGraw Hill LLC. All Rights Reserved.Term Step 4: Enter the p-value.(Round to 3 decimal places.)0.081(b) Based on your answer to part (a), which statement below is true?0000Z=-1.745ExplanationCheck0.1-ENSince the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected.Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected.Since the p-value is greater than the level of significance, the null hypothesis is rejected.Since the p-value is greater than the level of significance, the null hypothesis is not rejected.XXⒸ2022 McGraw Hill LLC. All Rights Reserv

GivenH0:μ=6H1:μ≠6The value of the test statistic on the sample is -1.745The P-value is 0.081Level of…

Answered: ose there is a claim that a certain…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Successful hotel managers must have personality characteristics often traditionally stereotyped as feminine (such as "compassionate") as well as those traditionally stereotyped as masculine (such as "forceful"). The Bem Sex-Role Inventory (BSRI) is a personality test that gives separate ratings for "female" and "male" stereotypes, both on a scale of 1 to 7. Although the BSRI was developed at a time when these stereotypes were more pronounced, it is still widely used to assess personality types. Unfortunately, the ratings are often referred to as femininity and masculinity scores. A sample of 148 male general managers of three-star and four-star hotels had mean BSRI femininity score x = 5.29. The mean score for the general male population is u = 5.19. Do hotel managers, on the average, differ significantly in femininity score from men in general? Assume that the standard deviation of scores in the population of all male hotel managers is the same as the o = 0.78 for the adult male…
Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 74.4 96 83.2 65 63.9 64.3 74.4 69 68.4 88 Test grades are believed to be normally distributed.Use a significance level of 5%. State the alternative hypothesis: HA:HA: μ>65μ>65 μ<65μ<65 μ≠65μ≠65 State the mean of the sample: (Round to two decimal places.) State the standard error of the sample means: (Round to four decimal places.) State the test statistic: t=t= (Round to four decimal places.) State the p-value: (Round to four decimal places.) Decision: Reject the null hypothesis. Do not reject the null hypothesis.
Statistics students believe that the mean soore on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 96 69 83.2 69 65 85.5 74.4 65 85.5 66.5 Test grades are believed to be normally distributed. Use a significance level of 5%. A. State the alternative hypothesis: H: Ομ 65 B. State the mean of the sample: (Round to two decimal places.) C. State the standard error of the sample means: (Round to four decimal places.) D. State the test statistic: t = (Round to four decimal places.) E. State the D-value; (Round to four decimal places.) F. Decision: O Do not reject the null hypothesis. O Reject the null hypothesis. Submit Question
A concerned consumer believes that they are being cheated in the weight of potato chips per bag. The company claims that every small bag weighs 1 ounce. You weigh 50 different bags of chips and find the average to be .97 ounces. Match the following terms to their meaning in context of this problem. The consumer finds a test result that is NOT statistically significant What is their conclusion?
You are playing a dice game with a friend and become suspicious that he is using weighted dice. So you stop the game, take one of his dice, and roll it 100 times. The results are in the table below. Do these results provide significant evidence that the proportion of times the dice lands on the six numbers are unequal? Calculate the chi-squared test statistic and the range the p-value falls in for this test. Number on die 1 2 4 Frequency 16 21 6 26 13 18 test statistic = 14.12, p-value in (.01, .025) test statistic = 24.368, p-value in (.005, .01) test statistic = 14.12, p-value in (.025, 05) test statistic = 24.368, p-value less than .005 O none of these
The college physical education department offered an advanced first aid course last summer. The scores on the comprehensive final exam were normally distributed, and the z-scores for some of the students are shown below. Robert 1.24 Juan 1.66 Haley −1.84 Joel 0.00 Jan −0.84 Linda 1.68 Which of these students scored above the mean? (Select all that apply.) Which of these students scored on the mean? (Select all that apply.) Which of these students scored below the mean? (Select all that apply.) If the mean score was μ = 140 with standard deviation σ = 15, what was the final exam score for each student?
Check My Work (4 remaining) Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows. Current Year Previous Year Occupied Rooms 1,505 1,411 Total Rooms 1,750 1,700 a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Let pi = population proportion of rooms occupied for current year p2 = population proportion of rooms occupied for previous year Ho : Pi – P2 equal to 0 H. : Pi – P2 equal to 0 b. What is the estimated proportion of hotel rooms occupied each year (to 2 decimals)? Current year Previous Year c. Conduct a hypothesis test. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. p-value = Using a 0.05 level of significance, what is your conclusion? We - Select your answer -…
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. A sample of 24 night students and 28 day students and their GPA's are recorded below. Test the claim using a 1% level of significance. Assume the population variances are unequal and that GPAs are normally distributed. Give answers to 4 decimal places. GPA-Night GPA-Day 3.05 3.38 2.91 3.02 3.27 3.4 3.29 2.73 3.3 3.24 3.35 2.69 3.39 3.25 3.52 3.33 3.39 2.33 3.25 3.51 3.08 3.07 3.27 2.9 3.32 3.48 3 2.94 3.62 2.93 3.64 3.31 3.54 2.62 3.45 2.66 3.29 3.27 3.56 2.76 3.15 2.7 3.4 3.27 3.51 2.96 3.54 2.86 3.24 2.72 2.64 3.14 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem.H0: Select an answer x̅₂ s² x̅₁ σ² μ₂ μ₁ p ? = ≠ > < ≥ ≤ Select an answer 0 μ₂ x̅₂ x̅₁ σ² p s² μ₁ H1: Select an answer σ² x̅₂ x̅₁ μ₁ μ₂…
Español A coin-operated coffee machine made by BIG Corporation was designed to discharge a mean of 7.2 ounces of coffee per cup. BIG has good reason to believe that the mean amount of coffee dispensed by the machine, u, is greater than 7.2 ounces, and plans to do a statistical test of the claim that the machine is working as designed. Technicians gather a random sample of fill amounts and find that the mean of the sample is 7.6 ounces and that the standard deviation is 0.5 ounces. Based on this information, complete the parts below. (a) What are the null hypothesis H. and the alternative hypothesis H, that should be used for the test? Ho :0 O
Hypothesis Testing Review For each problem below, simply identify the null and alternative hypotheses. Use appropriate notation/symbols. You do not have to run any hypothesis tests, although it's good practice and I'll post answers for all of them. 1) A simple random sample of 44 men from a normally distributed population results in a standard deviation of 10.7 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. 2) In 1997, a survey of 880 households showed that 145 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level.
Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 73.5 88 63.9 85.5 62.7 65 83.2 61.9 88 62.7 Test grades are believed to be normally distributed.Use a significance level of 5%. State the alternative hypothesis: HA:HA: μ>65μ>65 μ<65μ<65 μ≠65μ≠65 State the mean of the sample: State the standard error of the sample means: State the test statistic: t=t= State the p-value: Decision: Fail to reject the null hypothesis. Reject the null hypothesis.
The mean price of mid-sized cars in a region is $57,600. A test is conducted to see if the claim is true. Identify the null hypothesis. ? v? v Identify the alternative hypothesis. ? v:?v| ? v Identify the type I error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not $57,600. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is nor $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is $57,600. Identify the type II error. O You decide that the mean price of mid-sized cars is not $57,600, when the mean price of mid- sized cars actually is $57,600. O You decide that the mean price of mid-sized cars is $57,600, when the mean price of mid- sized cars actually is not…

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