### Confidence Intervals Calculation#### Instructions:Use the sample information \( \bar{x} = 36 \), \( \sigma = 4 \), \( n = 13 \) to calculate the following confidence intervals for \( \mu \) assuming the sample is from a normal population.---**(a) 90 percent confidence. (Round your answers to 4 decimal places.)**- The 90% confidence interval is from __ to __**(b) 95 percent confidence. (Round your answers to 4 decimal places.)**- The 95% confidence interval is from __ to __**(c) 99 percent confidence. (Round your answers to 4 decimal places.)**- The 99% confidence interval is from __ to __**(d) Describe how the intervals change as you increase the confidence level.**- ☑ The interval gets narrower as the confidence level increases. (Note: This statement seems contradictory. Higher confidence levels generally result in wider intervals. Ensure to verify and adjust your understanding.)---### Explanation:This exercise demonstrates the calculation of confidence intervals based on sample data from a normal distribution. Using the provided sample mean (\(\bar{x}\)), population standard deviation (\(\sigma\)), and sample size (\(n\)), students are to compute the confidence intervals at varying levels of confidence (90%, 95%, and 99%). This not only applies statistical formulas but also helps in understanding how confidence levels impact interval width.

Name: ### Confidence Intervals Calculation#### Instructions:Use the sample
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: ### Confidence Intervals Calculation#### Instructions:Use the sample information \( \bar{x} = 36 \), \( \sigma = 4 \), \( n = 13 \) to calculate the following confidence intervals for \( \mu \) assuming the sample is from a normal population.---**(a

Note: Hi there! Thank you for posting the question. As there are multiple sub-parts, according to…

Math

Statistics

Use the sample information x= 36, o = 4, n= 13 to calculate the following confidence intervals for µ assuming the sample is from normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to

Use the sample information x= 36, o = 4, n= 13 to calculate the following confidence intervals for µ assuming the sample is from normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Use the sample Information a = 36, o = 6, n= 11 to calculate the following confidence Intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence Interval Is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence Interval is from to
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Construct the indicated confidence interval for the population mean u using the t-distribution. Assume the population is normally distributed. c= 0.95, x= 14.7, s=4.0, n=5 ts The 95% confidence interval using a t-distribution is ( D. (Round to one decimal place as needed.)
Use technology to construct the confidence intervals for the population variance o² and the population standard deviation a. Assume the sample is taken from a normally distributed population. c=0.99, s= 33, n= 16 The confidence interval for the population variance is ( ). (Round to two decimal places as needed.) The confidence interval for the population standard deviation is ( ). (Round to two decimal places as needed.)
A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their school
es A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is 0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence interval for the population mean length of the skulls of this species of bird. You may want to use one of these: qt (p-0.10, df-11, lower. tail-FALSE)=1.36343 qt(p-0.05, df-11, lower.tail-FALSE) =1.795885 qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552 qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854 O (4.945, 5.635) O (4.913, 5.667) O (5.021, 5.559) O (5.181, 5.399)
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 75 dates, the mean record high daily temperature in a certain city has a mean of 82.74°F Assume the population standard deviation is 13.95°F. The 90% confidence interval is ( D (Round to two decimal places as needed.) The 95% confidence interval is ( ). (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. TO The 90% confidence interval O The 95% confidence interval Interpret the results. OA. You can be certain that the mean record high temperature was within the 90% confidence interval for approximately 68 of the 75 days, and was within the QE0L confidonco Intorval for annrovimatoly 71 nf the 7E dave
Find the following. Enter your answer rounded to at least two decimals. z a/2 for the 97% confidence interval
n1=16 x‾1=124 s1=35 n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 70 dates, the mean record high daily temperature in a certain city has a mean of 86.37°F Assume the population standard deviation is 14.38 F The 90% confidence interval is ( I) (Round to two decimal places as needed.) The 95% confidence interval is ( D (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. The 90% confidence interval The 95% confidence interval Interpret the results. O A. You can be 90% confident that the population mean record high temperature is between the bounds of the 90% confidence interval, and 95% confident for the G50% intonial Click to select your answer(S). 180min ZoT oo
solve for the image below
Use the sample information I= 36, 0 = 4, n= 13 to calculate the following confidence intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from to (d) Describe how the intervals change as you increase the confidence level. O The interval gets narrower as the confidence level increases. O The interval gets wider as the confidence level decreases. The interval gets wider as the confidence level increases. O The interval stays the same as the confidence level increases. 3:32 PM 10/25/2020 %23 O e to search