Use the sample information = 36, 0 = 4, n 13 to calculate the following confidence intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from| to (d) Describe how the intervals change as you increase the confidence level. O The interval gets narrower as the confidence level increases. O The interval gets wider as the confidence level decreases. O The interval gets wider as the confidence level increases. as the confidence level increases.

Use the sample information = 36, 0 = 4, n 13 to calculate the following confidence intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from| to (d) Describe how the intervals change as you increase the confidence level. O The interval gets narrower as the confidence level increases. O The interval gets wider as the confidence level decreases. O The interval gets wider as the confidence level increases. as the confidence level increases.

Name: Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to calculate the following confidence intervals for $ \mu $ assuming the sample is from a normal population.(a) 90 percent confidence. **(Round your answers to 4 decimal places.)**T

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Construct a confidence interval of the population proportion at the given level of confidence. NOTE:…

A: The question is about confidence intervalGiven :For ( a ) part :No. of successes ( x ) = 105No. of…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

A: Given information N = 1200, Margin of error E = 0.03 p = 0.79

Q: Use the data about the sample to calculate a 95% confidence interval for the average income of…

A: 1. The conditions for using t-distribution are: Sample size is small. Population standard deviation…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3 Since the population…

Q: tc for a 0.99 confidence level when the sample is 9. (Round your answer to three decimal places.)

Q: Find the 95% confidence interval for the proportion of customers planning to buy the shoes, and…

A: Provided data is, Mary was successful and collected 600 responses in time. 195 of the surveyed…

Q: Beth wants to determine a 90% confidence interval for the proportion of high school students in a…

A: We have given that, Population proportion (p) = 0.57, margin of error (E) = 0.04 and confidence…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below E = Width2…

Q: Use the given data to construct a confidence interval for the population proportion p of the…

A: From the provided information,x = 49, n = 68, confidence level = 99.5%p̂ = 49/68 = 0.696

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X ± Z s √(n) Where: X is the mean Z is the Z-value…

Q: Billy wants to estimate the percentage of students who live more than three miles from the school.…

A: The 95% confidence interval:The 95% confidence interval for the population proportion, π is such…

Q: . A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: The 95% confidence interval for proportion of fans who love music of David Wilcox is 0.74 to 0.86

Q: Use the confidence interval to find the margin of error and the sample mean. (0.072,0.210) The…

A: Note:- "Since you have posted multiple questions, we will provide the solution only to the first…

Q: Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals…

Q: Construct the 99% confidence interval for the difference when 3-47688, -318.32, -42.11, -2680, -19,…

A: Test hypothesisNull Hypothesis H0: μ1=μ2Alternative Hypothesis Ha: μ1≠μ2For group 1 Sample size…

Q: You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You…

A: Suppose p is the true population proportion of workforce has two or more jobs.

Q: Out of 600 people sampled, 30 had children under the age of 18. Based on this, construct a 99%…

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: p^ = 0.5390% ci for p is : (0.448,0.612)based on this ci we have to find the given statement is true…

Q: You are interested in constructing a 99% confidence interval for the proportion of all caterpillars…

A: Given n=417 X=45

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Here given Sample mean = 95.3 Population standard deviation = 6.5 And n = Sample size = 104 Here…

Q: Find z given a 94% confidence interval and a= 0.06. z = ?

A: Confidence level=94%

Concept explainers

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

Topic Video

Question

Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to calculate the following confidence intervals for $ \mu $ assuming the sample is from a normal population.

(a) 90 percent confidence. **(Round your answers to 4 decimal places.)**

The 90% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(b) 95 percent confidence. **(Round your answers to 4 decimal places.)**

The 95% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(c) 99 percent confidence. **(Round your answers to 4 decimal places.)**

The 99% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(d) Describe how the intervals change as you increase the confidence level.

- ⭕ The interval gets narrower as the confidence level increases.
- ⭕ The interval gets wider as the confidence level decreases.
-

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 28 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Proportions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

If n=190 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals.
If n = 140 and ˆpp^ = 0.25, construct a 99% confidence interval.Give your answers to three decimals
If n = 100 and ˆpp^ (p-hat) = 0.9, construct a 95% confidence interval.Give your answers to three decimals
If n = 500 and ˆpp^ (p-hat) = 0.2, construct a 99% confidence interval.
If n=440 and ˆpp^ (p-hat) = 0.08, construct a 99% confidence interval.
If n = 300 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals <p<
If n=280 and ˆpp^ = 0.15, construct a 90% confidence interval. Give your anwers to three decimals.
If n = 440 and ˆpp^ = 0.52, construct a 90% confidence interval.Give your answers to three decimals < p <
A random sample of 1000 people was taken and a 95% confidence interval for the average income in thousands is (30, 70). What would be a 90% confidence interval based on the same sample? Assume the population standard deviation \sigmaσ is known.
We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 245 had kids. Based on this, construct a 99% confidence interval for the proportion of adult residents who are parents in this county. If n = 560 and ˆpp^ = 0.6, construct a 95% confidence interval.
If n=580n=580 and ˆp=0.89p^=0.89, find the margin of error at a 90% confidence level.
If n = 600 and ˆpp^ (p-hat) = 0.85, construct a 99% confidence interval. Round three places.