Use the sample information = 36, 0 = 4, n 13 to calculate the following confidence intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from| to (d) Describe how the intervals change as you increase the confidence level. O The interval gets narrower as the confidence level increases. O The interval gets wider as the confidence level decreases. O The interval gets wider as the confidence level increases. as the confidence level increases.

Use the sample information = 36, 0 = 4, n 13 to calculate the following confidence intervals for u assuming the sample is from a normal population. (a) 90 percent confidence. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) 95 percent confidence. (Round your answers to 4 decimal places.) The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from| to (d) Describe how the intervals change as you increase the confidence level. O The interval gets narrower as the confidence level increases. O The interval gets wider as the confidence level decreases. O The interval gets wider as the confidence level increases. as the confidence level increases.

Name: Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to calculate the following confidence intervals for $ \mu $ assuming the sample is from a normal population.(a) 90 percent confidence. **(Round your answers to 4 decimal places.)**T

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Construct a confidence interval of the population proportion at the given level of confidence. NOTE:…

A: The question is about confidence intervalGiven :For ( a ) part :No. of successes ( x ) = 105No. of…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

A: Given information N = 1200, Margin of error E = 0.03 p = 0.79

Q: Use the data about the sample to calculate a 95% confidence interval for the average income of…

A: 1. The conditions for using t-distribution are: Sample size is small. Population standard deviation…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3 Since the population…

Q: tc for a 0.99 confidence level when the sample is 9. (Round your answer to three decimal places.)

Q: Find the 95% confidence interval for the proportion of customers planning to buy the shoes, and…

A: Provided data is, Mary was successful and collected 600 responses in time. 195 of the surveyed…

Q: Beth wants to determine a 90% confidence interval for the proportion of high school students in a…

A: We have given that, Population proportion (p) = 0.57, margin of error (E) = 0.04 and confidence…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below E = Width2…

Q: Use the given data to construct a confidence interval for the population proportion p of the…

A: From the provided information,x = 49, n = 68, confidence level = 99.5%p̂ = 49/68 = 0.696

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X ± Z s √(n) Where: X is the mean Z is the Z-value…

Q: Billy wants to estimate the percentage of students who live more than three miles from the school.…

A: The 95% confidence interval:The 95% confidence interval for the population proportion, π is such…

Q: . A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: The 95% confidence interval for proportion of fans who love music of David Wilcox is 0.74 to 0.86

Q: Use the confidence interval to find the margin of error and the sample mean. (0.072,0.210) The…

A: Note:- "Since you have posted multiple questions, we will provide the solution only to the first…

Q: Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals…

Q: A statistics practitioner took a random sample of 47 observations from a population whose standard…

A: From the given information, it is clear that, Sample mean X=99 Population standard deviation σ=27…

Q: Construct the 99% confidence interval for the difference when 3-47688, -318.32, -42.11, -2680, -19,…

A: Test hypothesisNull Hypothesis H0: μ1=μ2Alternative Hypothesis Ha: μ1≠μ2For group 1 Sample size…

Q: You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You…

A: Suppose p is the true population proportion of workforce has two or more jobs.

Q: Out of 600 people sampled, 30 had children under the age of 18. Based on this, construct a 99%…

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: p^ = 0.5390% ci for p is : (0.448,0.612)based on this ci we have to find the given statement is true…

Q: You are interested in constructing a 99% confidence interval for the proportion of all caterpillars…

A: Given n=417 X=45

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Here given Sample mean = 95.3 Population standard deviation = 6.5 And n = Sample size = 104 Here…

Q: Find z given a 94% confidence interval and a= 0.06. z = ?

A: Confidence level=94%

Concept explainers

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

Topic Video

Question

Use the sample information $ \bar{x} = 36, \sigma = 4, n = 13 $ to calculate the following confidence intervals for $ \mu $ assuming the sample is from a normal population.

(a) 90 percent confidence. **(Round your answers to 4 decimal places.)**

The 90% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(b) 95 percent confidence. **(Round your answers to 4 decimal places.)**

The 95% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(c) 99 percent confidence. **(Round your answers to 4 decimal places.)**

The 99% confidence interval is from $\_\_\_\_$ to $\_\_\_\_$

(d) Describe how the intervals change as you increase the confidence level.

- ⭕ The interval gets narrower as the confidence level increases.
- ⭕ The interval gets wider as the confidence level decreases.
-

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 28 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Proportions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

If n = 580 and ˆpp^ (p-hat) = 0.35, construct a 95% confidence interval.
If n = 140 and ˆpp^ (p-hat) = 0.7, construct a 90% confidence interval.Give your answers to three decimals< p <
Suppose that scores on Statistics final exam of Business School in UK are normally distributed. To estimate the average score on the exam for all students, I take my class as a random sample of size 25. The sample yielded mean, = 35 and sample standard deviation, s = 15. Give a 95% confidence interval for the average score on the final exam of Statistics for all Business School students. *(no use EXCEL)
In a survey, a random sample of teenagers were asked whether they have a sibling. The resulting confidence interval for the proportion of teenagers who have a sibling is (.61,.91). What is the sample proportion, p^?
N1=94 X1=26 N2=78 X2=39 Confidence interval 99% ?
what is the value for x^2 left for a 95 confidence interval when n=18
If n=190 and ˆpp^ (p-hat) =0.29, find the margin of error at a 90% confidence levelGive your answer to three decimals
Out of 100 people sampled, 31 had children. Based on this, construct a 95% confidence interval for the true population proportion of people with children. Preliminary: Verify ��^(1-�^)≥10. Round your answer to one decimal place. ��^(1-�^)= Confidence Interval: What is the 95% confidence interval to estimate the population proportion? Round your answer to three decimal places. <�<
How do I find the point estimate s^2? I was wondering about the formula used for excel as well.
How can I find the 95% confidence interval for a hazard ratio based on theta1 and theta2 from an exponential distribution? Please can you give an example?
If n=110 and �^ (p-hat) =0.3, find the margin of error at a 90% confidence levelGive your answer to three decimals
Find the standard error of the sample mean such that we have 60 random samples with mean 25 and standard deviation of 13. (Round to 3dp)