If n = 500 and ˆpp^ (p-hat) = 0.2, construct a 99% confidence interval.
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A: Given n = 580 p^ (p-hat) = 0.35,
Q: If n = 600 and ˆpp^ (p-hat) = 0.85, construct a 99% confidence interval. Round three places.
A: From the provided information, Sample size (n) = 600 Sample proportion (p̂) = 0.85 Confidence level…
Q: If n=280 and ˆpp^ (p-hat) = 0.39, construct a 95% confidence interval. Give your answers to three…
A: The given sample size, n=280. The sample proportion, p^=0.39 The level of confidence is 0.95. Need…
Q: If n=440 and ô (p-hat) = 0.08, construct a 99% confidence interval. Give your answers to three…
A: From the provided information, Sample size (n) = 440 and p̂ = 0.08 Confidence level = 99%
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Q: If n=580n=580 and ˆp=0.89p^=0.89, find the margin of error at a 90% confidence level.
A: For 90% confidence intervalα=1-CI=1-0.90=0.10So, zα2=z0.102=z0.05=1.645
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Q: If n = 600 and ˆpp^ (p-hat) = 0.25, construct a 95% confidence interval.
A: Given that sample size is n = 600 And the sample proportion is 0.25 At 95% confidence level, the…
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Q: If n=410 and ˆpp^ (p-hat) = 0.35, construct a 90% confidence interva
A: Given: n=410 Confidence level=90%
Q: If n = 560 and ˆpp^ (p-hat) = 0.25, construct a 99% confidence interval.
A: Calculations: x=140 and N= 560
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A: Given Information: Degrees of freedom df=24 Confidence level = 95% = 0.95 Significance level…
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A: Given information- Sample size, n = 490 Confidence level, c = 99% Significance level, α = 0.01…
Q: If n = 500 and ˆpp^ (p-hat) = 0.65, construct a 99% confidence interval. Give your answers to three…
A: Given,sample size(n)=500sample proportion(p^)=0.65α=1-0.99=0.01α2=0.005Z0.005=2.58
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Q: = 140 and ˆpp^ (p-hat) = 0.7, construct a 90% confidence interval. Give your
A: The value of z at a 90% confidence level is 1.645, which can be obtained by using the standard…
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A: Sample size n = 110 Sample proportion p^ = 0.71 Confidence level = 90% Formula Used: Margin of error…
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Q: If n = 140 and ˆpp^ = 0.25, construct a 99% confidence interval.Give your answers to three decimals
A: It is given that p̂ is 0.25 and n is 140.
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A: Sample size, n = 100 95% confidence level p^ = 0.9
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Q: If n = 420 and ˆpp^ (p-hat) = 0.7, construct a 90% confidence interval. Give your answers to three…
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Q: If n = 420 and ˆpp^ (p-hat) = 0.05, construct a 95% confidence interval. Round three places.
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Q: If n = 560 and ˆpp^ (p-hat) = 0.5, construct a 95% confidence interval. Give your answers to three…
A: Solution : Given : n = 560 p^ = 0.5 The critical value for α=0.05 is zc=z1−α/2=1.96 The…
Q: If n = 300 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval. Give your answers to three…
A: n=300p^=0.95 Confidence level: 1-α=0.99
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Q: If n=130 and ˆpp^ (p-hat) = 0.1, construct a 99% confidence interval. Give your answers to three…
A: Given, Sample size, n = 130 Sample proportion, p^ = 0.1 Level of significance = 1 - 0.99 = 0.01…
Q: construct a 90% confidence interval.
A:
If n = 500 and ˆpp^ (p-hat) = 0.2, construct a 99% confidence interval.
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- Express the confidence interval (3.6%,21%)(3.6%,21%) in the form of ˆp±MEp^±ME.A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s = 17.6 milligrams. Assuming the population has a normal distribution, construct a 95% confidence interval for the true mean cholesterol content of all such eggs. You may compute this by hand or use technology. << (Round your final answer to 1 decimal)A survey collected data on attitudes toward the quality of customer service in retail stores. The survey found that 270 of the 750 American adults sampled felt that customer service is better today than it was two years ago. Find a 94% confidence interval for the proportion of American adults who feel customer service is better today than it was two years ago. p^±z⋅CFp^(1−p^)n−−−−−√p^±z⋅CFp^(1−p^)n Note: Since the population is filled with words, μμ and σσ dont exist. We are trying to estimate a proportion here. What is p^p^ ? ["", "", "", ""] What is the value for z? ["", "", "", ""] What is CF? ["", "", "", ""] What is n?
- The mean of a distribution is 15 and the standard deviation is 3. Use Chebyshev's Theorem and the formula 1 - 1 / (k ^ 2) to determine the minimum percentage of values that will fall between 9 and 21Describe about the Confidence Interval for μD.You want to examine the effectiveness of a new tutoring program at SWC. A sample of n=9 stats students is used to evaluate t. Each students grade point average is recorded before the program and after the program. The average GPA improved by Mp=0.60 points with s^2 =0.09. the researcher would like to use the sample to estimate how much effect the workshop would have for the entire college population. Which of the following is the 80% confidence interval for these data? A. μD=0.60 + 0.10(1.397) B. μD=0.60 + 0.09(1.860) C. μD=0.60 + 0.01(1.397) D. μD =0.60 + 0.10(1.860)
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- A thread manufacturer wants to estimate the mean tensile strength of a particular type of thread. A random sample of 15 examples of the thread are tested. The mean tensile strength of the sample is 7.64 pounds with a sample standard deviation of 0.48 pounds. Construct a 95% confidence interval for the mean tensile strength of that type of thread. In the next question, you will enter the upper limit of the interval. For now, enter the lower limit of the interval, rounded to two decimal places.A clinical trial is run to investigate the effectiveness of an experimental drug in reducing high blood pressure in women to a drug considered standard care and to placebo. Women are enrolled and randomly assigned to receive either the experimental drug, the standard drug or placebo. Women are followed through for (< 37 weeks) or not. The data are shown below. Is there a statistically significant difference in the proportions of women having high blood pressure among the three treatment groups? Run the test at a 5% level of significance. Appropriate test? Decision Rule? Test Statistic? Yes No Total Experimental Drug 7 33 40 Standard Drug 13 32 45 Placebo 17 18 35 Total 37 83 120A research company wants to estimate the mean IQ score for the population of all high school students. If the population standard deviation is 30,what is the minimum number of high school students should be selected for IQ tests if the company wants 95% confidence that the sample mean will be within 3 IQ points of the population mean?