Use the sample information _                                                  X   =40, o=3, n= 13 to calulate the following confidene intervals for u assuming the sampe if from a normal population.   1.    90 percent confidence interval is from                   ? to ?   2. 95 percent confidence. The 95 percent confidence interval is from                ?to ? 3. 99 percent confidence  The 99 percent confidcee interval is from               ?to ?

Q: Last Wednesday, a random sample of 12 students were surveyed to find how long it takes to walk from…

A: Sample mean = x̅ = 10 Sample size = n = 12 Sample S.D = s = 2.5

Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

A: Solution: From the given information, n=32, d-bar=1.358, α=0.05 and sd=0.635.

Q: Two-Population Intervals: 8. How long do new batteries last on a camping trip? A random sample of n,…

A:

Q: Consider a 90% confidence interval for mu Assume is not knownFor which sample size, n = 23 or n = 17…

A: With increase in size, the standard error gets decrease so confidence interval is shorter. So…

Q: In a sample of 50 people the average score was 380 with a standard deviation of 3.53. What is the…

A: Sample size (n) = 50Sample mean (x̅) = 380Standard deviations (s) = 3.53 Significance level (α) = 1-…

Q: The data attached are the systolic blood pressure of 10 subjects collected before and after…

A: The systolic blood pressure of 10 subjects collected before and after exercise.

Q: In a random sample of 22 people, the mean commute time to work was 34.3 minutes and the standard…

A: From the provided information, Sample size (n) = 22 Sample mean (x̅) = 34.3 Sample standard…

Q: Give a 99.8% confidence interval, for 41 - P2 given the following information. = 55, = 2.17, s =…

A:

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: [CONF - 03] Osmanthus wine has an average ethanol concentration of 35%. If the standard deviation of…

A:

Q: Please carect answers fast

A: The objective of the question is to find the sample mean and the margin of error from the given 99%…

Q: Suppose that textbook weights are normally distributed. You measure 36 textbooks' weights, and find…

A: We have to find given probability.

Q: Out of 400 people sampled, 268 had kids. Based on this, construct a 99% confidence interval for the…

A: A sample of 400 people are considered in which 268 had kids. The proportion of people with kids is,…

Q: Here are summary statistics for randomly selected weights of newborn girls: n= 177, x 28.1 hg, s=7.7…

A: Answer:----.                                   Date:----26/09/2021

Q: You measure 29 textbooks' weights, and find they have a mean weight of 31 ounces. Assume the…

A: Given : x¯ = 31 n = 29  σ = 3.9 At 90% confidence level, α = 0.1 zα2=z0.05 = 1.645

Q: Use the given confidence interval to find the margin of error and the sample mean. (12.3,20.7) The…

A: We have given that confidence interval CI = ( 12.3, 20.7 )

Q: You may need to use the appropriate appendix table or technology to answer this question. Sales…

A:

Q: A candom sample of 13 subjects was asked to perform a given task. The time in seconds it took each…

A:

Q: • In the discussion for week 4, you rolled a pair of dice 10 times and calculated the average sum of…

A: Given: For a pair of dice rolled 10 times  Sample size (n) = 10 Sample mean = 5.9 Sample standard…

Q: 20, 19, 25, 27, 26, 21, 26, 19, 18, 16, 28, 19, 21, 23 1.0134986 Consider the sample: Q1. What is…

A: Here given that  Sample:   20,19,25,27,26,21,26,19,18,16,28,19,…

Q: In a survey of 2094 adults in a recent year, 1356 say they have made a New Year's resolution.…

A: From the survey of 2094 adults in a recent year, 1356 say that they have made a new year's…

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data,  Less attendance Full attendance 90 96 90 96 60 100 50 99 69   88…

Q: If n = 5, T-46, and s= 13, construct a confidence interval at a 80% confidence level. Give your…

A:

Q: From the given information, I need to: -Explain why the t-distribution is used. State the…

A:

Q: In a recent study of 42 eighth graders, the mean number of hours per week that they watched…

A: x̄=19.6 , ?=5.8 , n=42, C.I=98%=0.98

Q: None

A: The problem revolves around a local golf course owner who aims to determine the average age of the…

Q: You would like to construct a hypothesis test to see if the average distance (in miles) a package is…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: If n = 310 and X = 248, construct a 99% confidence interval for the population proportion, p. Give…

A: According to the given information in this question  We need to find the 99% confidence interval

Q: se applicants college is giv confidence interval uses the sample mean and the sample standard…

A: Given that,The 99% confidence interval is (1695,1840)and sample size (n) = 25

Q: A packet of garden seeds contains 250 seeds. The information printed on the packet indicates that…

A: Given , n = 250

Q: A normally distributed population is having standard deviation 2.8, a sample of 28 is taken randomly…

A: Answer: From the given data, Sample size(n) = 28 mean (X¯) = 15.5 Standard deviation(σ) = 2.8 98%…

Q: The mean age from a sample of 45 employees at Stats R Us is 22, with a standard deviation of 4.32.…

A: Sample mean = x̅ = 22 Sample size = n = 45 Sample S.D = s = 4.32 Standard Error = s/√n  =…

Q: times to work, It was found that the population standard deviation is 9.2 minutes. Find the margin…

A: It is given that Sample mean = 34.5Population standard deviation = 9.2Sample size = 8Confidence…

Q: 15.52) Find the necessary sample size. 2) A population is normal with a variance of 99. Suppose vou…

A:

Q: The table provides summary statistics on highway fuel economy of cars manufactured in 2012 (from…

A: Given data:Hwy MPG, Automatic (consider sample-1)Hwy MPG, Manual (consider sample-2)Mean;…

Q: 4. A random sample of 50 individuals are asked of the number of hours spent on social media on a…

A: Suppose that is the population mean number of hours spent on social media per day.

Q: please use the calculator method      The scores on the Wechsler Intelligence Scale for Children…

A: Confidence Interval l1  = X - tα  S. E. of X  - Lower limitl2  = X  +  tα  S. E. of X  - Upper limit…

Q: You measure 35 backpacks' weights, and find they have a mean weight of 79 ounces. Assume the…

A: Given: In case of known standard deviation (σ), we apply  Z-distribution in order to compute the 99%…

Q: Sample of two different models of cars were selected, and the actual speed for each car was…

A: The formula for finding the confidence interval can be written as: Here n is the sample size.…

Q: 12) The sample means and margin of errors are given. Construct confidence intervals for the true…

A:

Q: How do I calculate a 90% confidence interval for a sample mean of 15 with a sample standard…

A:

Q: The distance a basketball player runs during a game is one of the many variables used for assessing…

A:

Q: Using the results below: M1 = 18.57, M2 = 18.33, SM1-M2 = 0.97, tcv = 1.997 1. Calculate a 95%…

A: It is given that M1=18.57, M2=18.33, SM1-M2=0.97 and tcv=1.997.

Q: The University of Illinois decided to conduct a study at their university. The 90% confidence…

A:

Q: UI 7 UBservations, the valués are 10, 11, 12, 13, 14, 15, 16. Find the 95% confidence interval for…

A: Given Sample size (n)=7

Q: Systolic Blood Pressure (SBP) of 13 workers follows normal distribution with standard deviation 10.…

A: We have given that,  The data set are :- 129, 134, 142, 114, 120, 116, 133, 142, 138, 148, 129, 133,…

Q: Construct a confidence interval for p, - P2 at the given level of confidence. x1 = 384, n, = 508, x2…

A: Obtain the 90% confidence interval for the difference between two population proportions. The 90%…

Q: C. s = 1.5, n = 5 %3D

A: Given: s=1.5 n=5 α=0.1

Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 3. (Round…

A: From the given information     Confidence level, CL  = 0.95    Sample size, n = 3 So, degrees of…