Dr. Higney, an academic researcher in an English department, wants to learn about the average length of a novel. In order to do this, Dr. Higney collects data on the word counts of 200 randomly selected novels. The sample mean of this data set is = 85252 with a sample standard deviation of 8413 words. Using this data, construct a 90% confidence interval for the true mean length of novels. (84,273.50, 86,230.51) (82719.67,89784.33) (94086.04, 96417.96) (80937.53, 90566.47)
Dr. Higney, an academic researcher in an English department, wants to learn about the average length of a novel. In order to do this, Dr. Higney collects data on the word counts of 200 randomly selected novels. The sample mean of this data set is = 85252 with a sample standard deviation of 8413 words. Using this data, construct a 90% confidence interval for the true mean length of novels. (84,273.50, 86,230.51) (82719.67,89784.33) (94086.04, 96417.96) (80937.53, 90566.47)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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![**Understanding Confidence Intervals in Novel Lengths**
Dr. Higney, an academic researcher in an English department, aims to study the average length of a novel. To achieve this, Dr. Higney collects data on the word counts of 200 randomly selected novels. Here's a summary of the data collected:
- **Sample Size (n):** 200 novels
- **Sample Mean (x̄):** 85,252 words
- **Sample Standard Deviation (s):** 8,413 words
**Task:**
Using this data, construct a 90% confidence interval for the true mean length of novels.
**Options for the 90% Confidence Interval:**
1. (84,273.50, 86,230.51)
2. (82,719.67, 89,784.33)
3. (94,086.04, 96,417.96)
4. (80,937.53, 90,566.47)
When constructing a confidence interval, it is essential to determine the range within which the true mean of the population is expected to fall, given a certain level of confidence (in this case, 90%).
To calculate the confidence interval, we use the formula:
\[ CI = x̄ \pm (z* \cdot \frac{s}{\sqrt{n}}) \]
Where:
- \( x̄ \) is the sample mean.
- \( z* \) is the z-value corresponding to the desired confidence level (for 90%, \( z* = 1.645 \)).
- \( s \) is the sample standard deviation.
- \( n \) is the sample size.
**Note:** The correct confidence interval should reflect these calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7e444e2-a441-4a28-bca8-26e04764874a%2Ff32d7653-08ac-4c33-944d-70a0474d3179%2F36w2bga_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Confidence Intervals in Novel Lengths**
Dr. Higney, an academic researcher in an English department, aims to study the average length of a novel. To achieve this, Dr. Higney collects data on the word counts of 200 randomly selected novels. Here's a summary of the data collected:
- **Sample Size (n):** 200 novels
- **Sample Mean (x̄):** 85,252 words
- **Sample Standard Deviation (s):** 8,413 words
**Task:**
Using this data, construct a 90% confidence interval for the true mean length of novels.
**Options for the 90% Confidence Interval:**
1. (84,273.50, 86,230.51)
2. (82,719.67, 89,784.33)
3. (94,086.04, 96,417.96)
4. (80,937.53, 90,566.47)
When constructing a confidence interval, it is essential to determine the range within which the true mean of the population is expected to fall, given a certain level of confidence (in this case, 90%).
To calculate the confidence interval, we use the formula:
\[ CI = x̄ \pm (z* \cdot \frac{s}{\sqrt{n}}) \]
Where:
- \( x̄ \) is the sample mean.
- \( z* \) is the z-value corresponding to the desired confidence level (for 90%, \( z* = 1.645 \)).
- \( s \) is the sample standard deviation.
- \( n \) is the sample size.
**Note:** The correct confidence interval should reflect these calculations.
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