Use the sample data and confidence level given below to complete parts (a) through (d). K A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=929 and x = 582 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. * 0.626 (Round to three decimal places as needed.) b) Identify the value of the margin of error E E=Q (Round to three decimal places as needed.).

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**Statistics Exercise: Estimating Population Proportion with Confidence Intervals**

In this exercise, we are analyzing data from a research institute poll regarding identity theft vulnerability. The poll includes responses from 929 individuals, with 582 indicating that they feel vulnerable to identity theft. We will use a 95% confidence level for our estimations.

### Instructions:

**a) Find the best point estimate of the population proportion \( p \):**

- The best point estimate of the population proportion \( p \) is calculated using the formula:
  \[
  \hat{p} = \frac{x}{n}
  \]
  where \( x = 582 \) (the number of respondents who said "yes") and \( n = 929 \) (the total number of respondents).
  
- **Point Estimate:**
  \[
  \hat{p} = \frac{582}{929} = 0.626
  \]
  *(Round to three decimal places as needed.)*

**b) Identify the value of the margin of error \( E \):**

- The margin of error \( E \) can be determined using the formula:
  \[
  E = Z \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
  \]
  where \( Z \) is the Z-score for the chosen confidence level (for 95%, \( Z \approx 1.96 \)).

- **Margin of Error Calculation:**
  - First, calculate the standard error:
    \[
    SE = \sqrt{\frac{0.626 \times (1-0.626)}{929}}
    \]
  - Then multiply by the Z-score to find \( E \).

*(Round the margin of error to three decimal places as needed.)*

### Additional Resources:

- To find Z-scores for various confidence levels, you may refer to a table of Z-scores.

This exercise provides a practical application of calculating point estimates and confidence intervals, essential concepts in statistical analysis.
Transcribed Image Text:**Statistics Exercise: Estimating Population Proportion with Confidence Intervals** In this exercise, we are analyzing data from a research institute poll regarding identity theft vulnerability. The poll includes responses from 929 individuals, with 582 indicating that they feel vulnerable to identity theft. We will use a 95% confidence level for our estimations. ### Instructions: **a) Find the best point estimate of the population proportion \( p \):** - The best point estimate of the population proportion \( p \) is calculated using the formula: \[ \hat{p} = \frac{x}{n} \] where \( x = 582 \) (the number of respondents who said "yes") and \( n = 929 \) (the total number of respondents). - **Point Estimate:** \[ \hat{p} = \frac{582}{929} = 0.626 \] *(Round to three decimal places as needed.)* **b) Identify the value of the margin of error \( E \):** - The margin of error \( E \) can be determined using the formula: \[ E = Z \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \] where \( Z \) is the Z-score for the chosen confidence level (for 95%, \( Z \approx 1.96 \)). - **Margin of Error Calculation:** - First, calculate the standard error: \[ SE = \sqrt{\frac{0.626 \times (1-0.626)}{929}} \] - Then multiply by the Z-score to find \( E \). *(Round the margin of error to three decimal places as needed.)* ### Additional Resources: - To find Z-scores for various confidence levels, you may refer to a table of Z-scores. This exercise provides a practical application of calculating point estimates and confidence intervals, essential concepts in statistical analysis.
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