Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2649 subjects randomly selected from an online group involved with ears. 1068 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval. 0
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- The National Association of Colleges and Employers sponsors the Graduating Student and Alumni Survey.Part of the survey gauges student optimism in landing a job after graduation. According to one year’s surveyresults, published in American Demographics, among the 1218 respondents, 733 said that they expecteddifficulty finding a job. Construct a 90% confidence interval for the proportion of students who expecteddifficulty finding a job. Interpret your result.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2335 subjects randomly selected from an online group involved with ears. 924 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. E Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=L (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. O A. One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. O B. One has 99% confidence that the sample…Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2460 subjects randomly selected from an online group involved with ears. 1005 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)
- Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2440 subjects randomly selected from an online group involved with ears. 1077 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2540 subjects randomly selected from an online group involved with ears. 1141 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2642 subjects randomly selected from an online group involved with ears. 1128 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2423 subjects randomly selected from an online group involved with ears. 923 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval. ]Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.09 margin of error, use a confidence level of 98%, and use results from a prior poll suggesting that 18% of adults have consulted fortune tellers. n=An online retailer has identified the maximum willingness of 10 consumers to pay for the same product. The 10 prices are: $10.00, $11.50, $9.50, $10.20, $11.20, $10.50, $9.80, $10.10, $9.90, $11.00 The retailer seeks a 95% confidence interval for the mean price consumers are willing to pay. The sample mean is calculated as $10.37, and the sample standard deviation is $0.66. Also consider the following t-values: Degrees of freedom 8 a. (9.99, 10.75) 9 10 90% confidence 1.86 1.833 1.812 95% confidence 2.306 2.262 2.228 99% confidence 3.355 3.250 3.169 Selecting the correct t-value, calculate the limits of the confidence interval.The Centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and Questions Navigation Menu inary estimate of the proportion who smoke of .26 a. How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02 (to the nearest whole number)? Use 95% confidence. b. Assume that the study uses your sample size recommendation in part (a) and finds 520 smokers. What is the point estimate of the proportion of smokers in the population (to 4 decimals)? c. What is the 95% confidence interval for the proportion of smokers in the population (to 4 decimals)?A survey was conducted that asked 1018 people how many books they had read in the past year. Results indicated that x = 14.3 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and OB. There is 90% confidence that the population mean number of books read is between OC. There is a 90% probability that the true mean number of books read is between and andRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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