Use the sample data and confidence level given below to complete parts (a) through (d).In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2577 subjects randomly selected from an online group involved with ears. 970 surveys werereturned. Construct a 90% confidence interval for the proportion of returned surveys.Click the icon to view a table of z scores.a) Find the best point estimate of the population proportion p.A(Round to three decimal places as needed.)an exampleGet more help.MacBook AirADIIF90Clear allF104Check ans

It is given that Favourable cases, X = 970 Sample size, n = 2577 Confidence level = 90%

Answered: Use the sample data and confidence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A study of seat belt yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke dy are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data? 5 sic Click the icon to view the data table. use. ..... Hа: Heavy Determine the test More info izlet. y of X-(Round to claim Number of Cigarettes Smoked per Day 15-34 Determine the P-v 1-14 35 and over le wh Wear Seat Belts 190 13 36 10 P-Value = (Rou Don't Wear Seat Belts 152 13 45 ww.nur y is that people ry supported by Use a 0.05 signific who smoke are les the sample data? nour seat Done theory is not zed in t Print O A. There is nd supported S Top eat belt. The O B. There is no theory is supportou Dy ao vampIG Gutu. O C. There is sufficient evidence to reject the claim that heavy smokers…
An article reported a survey of patients with Parkinson's disease. Of 161 patients who said they exercised regularly, 77 reported failing in the previous six months. Of 94 patients who said they did not exercise regularly, 48 reported falling in the previous six months. Can you conclude the proportion of patients who fall is less for those who exercise than for those who do not? Use the significance level of 0.05. Type the Computed Testing.
The average house has 15 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 16 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18, 15, 17, 14, 16, 17, 18, 15, 15, 14, 14, 14, 15, 15, 16, 18 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly more than 15 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in…
A dietitian wishes to see if a person's cholesterol level will change if the diet is supplemented by a certain mineral. Seven subjects were pretested and then took the mineral supplement for a six-week period. The results are shown below in the table. Use a paired samples t-chart at a = 0.01 significance level to see difference (Before - After) between the cholesterol levels. State the hypotheses and conclusion. Also, conduct a 99% confidence interval. Subject 1 Before 210 After 190 2 205 170 3 208 210 4 192 188 5 178 173 6 244 228 7 211 198
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Consider the relationship between p-values and significance levels. a. Explain why a value of z-statistic that is significant at the 1% level in a one-sided test is always significant at the 5% level. b. Explain why the reverse is not true. If something is significant at the 5% level in a one-sided test it is not necessarily significant at the 1% level.
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A researcher is looking into the price of round trip airline tickets between LA and NY. The five number summary for the data sets provided below: 1. 240 2.$3753.$ 450 4. $657 5. $890 Complete the following: 1. Interpret the value of the third quartile in a contextualized sentence: Blank (answer options: 25%, 50%, at least 50, at least 25, at least 75, 75%) of _(answer iptions: airline tickets, round trip airline tockets between LA and NY, the price of an airline ticket between Ny and La) are priced_(375 or less, 657, 450, 375, 657, 450) 2. Determine if a ticker priced at 1200 would be an outlier. A ticker priced at 1200 ( answer options: would, eould not) be considered an iutlier because 1200 is (within, not within)_(the interval 93 and 939, the interval -48 and 1080, within 3 sd's of the mean, two standard deviations of the mean)
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