Usethe sample data and confidence level given below to complete parts (a) through (d).In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2516 subjects randomly selected from an online group involved withears. 1001 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys.Click the icon to view a table of z scores.a) Find the best point estimate of the population proportion p.(Round to three decimal places as needed.)b) Identify the value of the margin of error E.E=(Round to three decimal places as needed.)c) Construct the confidence interval.C 20.00.10.20.30.40.50.60.70.80.91.01.2131.41.51.61.71.81.92.02.12.22.42.52.62.72.8293.03.13.23.33.43.50 and up2005000539857936179655468153257758078818159841388499002915293329452965496419713977296619063961896389963099859674996790009066996079000Cumulative Area from the LEFT.015040583262177291761179108186866690493207934594639649971997789826386499209940.9955.99759987999399970001NOTE: For of above 3.49, use 0.9999 for the re.025080547858716255662869857324764279398212346186868888906692229357547495739656972697835630186896229941966699679676POSITIVE z Scores999490065120561759108664701976737967848587089082937094349602973297889834987199019943995799779988999499970304516055575945633147007054.7389770479958508872980259099325183825495 .959196719738979398383875990499459959990999773984998805519956966736708814227734253187498944911592659094950595.999678974497989842900299946996099709978998999949997050652395325877271:23.74547764805183153554877029623279940695159601.968697509803984638819909993199489961997199799985998939229994999707527956758064644368087157348677948078834085778790806091479418975698089884991199329949997299799989999690000708531957146103648063447190751778233106830535998810200791623306942995359625309976198129854991:3993499519963997399803996999099939995999708535957536141661768797224354978528133838986218830901591775019944196459433970697679617969099169606996499749961900699609998Common Critical Values20.00.1020.3040.5060.70.80.91.01.21.41.51.61.71.81.9202.1222.3242526272.83.03.13.2333.43.50 and up2

Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.

Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

(Q1). The principal randomly selected six students to take an aptitude test in her school. Their scores were: 87 86 89 78 75 70 Assume that the population is normally distributed. a. What is the point estimate of the mean aptitude test score for this school? b. What is the margin of error when estimating the mean aptitude test score if using 95% confidence. c. Construct a 95% confidence interval estimate of the mean aptitude test score for this school.
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 3 percentage points and use a confidence level of 95%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n= (Round up to the nearest integer.) b. Assume that 25% of adults can wiggle their ears. n= (Round up to the nearest integer.) C
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 3 percentage points and use a confidence level of 90%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n= (Round up to the nearest integer.)
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.2,5.4) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is Search 6 17 + & 87 lyn 8 9 DYWAN DDI 8 0 0 0
In a survey of 2074 adults in a recent year, 744 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence The 90% confidence interval for the population proportion p is D. (Round to three decimal places as needed.)
Use the given confidence interval to find the margin of error and the sample mean. (15.3,23.7) The sample mean is . (Type an integer or a decimal.) The margin of error is. (Type an integer or a decimal.)
Use the given confidence interval to find the margin of error and the sample mean. (11.3,21.1) The sample mean is The margin of error is
Jse the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in cértain patients. In clinical trials, among 4334 patients treated with the drug, 12 developed the adverse reaction of nausea. Construct a 95% confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E =
Use the confidence interval to find the margin of error and the sample mean. (1.53,1.91) The margin of error is. (Round to two decimal places as needed.) The sample mean is (Type an integer or a decimal.) ts
Need help of the Find the Confidence Interval section
Use the confidence interval to find the margin of error and the sample mean. (1.62,1.90) The margin of error is (Round to two decimal places as needed.) The sample mean is
Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The sample mean is. (Type an integer or a decimal.) ES