Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.
Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:Use
the sample data and confidence level given below to complete parts (a) through (d).
In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2516 subjects randomly selected from an online group involved with
ears. 1001 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys.
Click the icon to view a table of z scores.
a) Find the best point estimate of the population proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
E=
(Round to three decimal places as needed.)
c) Construct the confidence interval.
C
<p<
(Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
O A. 95% of sample proportions will fall between the lower bound and the upper bound.
O B. One has 95% confidence that the sample proportion is equal to the population proportion.
O C. One has 95% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
O D. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

Transcribed Image Text:2
0.0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1.0
1.2
13
1.4
1.5
1.6
1.7
1.8
1.9
2.0
2.1
2.2
2.4
2.5
2.6
2.7
2.8
29
3.0
3.1
3.2
3.3
3.4
3.50 and up
2
00
5000
5398
5793
6179
6554
6815
3257
7580
7881
8159
8413
8849
9002
9152
9332
9452
9654
9641
9713
9772
9661
9063
9618
9638
9963
0
9985
9674
9967
9000
9066
99607
9000
Cumulative Area from the LEFT
.01
5040
5832
6217
7291
7611
7910
8186
8666
9049
3207
9345
9463
9649
9719
9778
9826
3864
9920
9940
.9955
.9975
9987
9993
9997
00
01
NOTE: For of above 3.49, use 0.9999 for the re
.02
5080
5478
5871
6255
6628
6985
7324
7642
7939
8212
3461
8686
8888
9066
9222
9357
5474
9573
9656
9726
9783
5630
1868
9622
9941
9666
9967
9676
POSITIVE z Scores
9994
9006
5120
5617
5910
8664
7019
7673
7967
8485
8708
9082
9370
9434
9602
9732
9788
9834
9871
9901
9943
9957
9977
9988
9994
9997
03
04
5160
5557
5945
6331
4700
7054
.7389
7704
7995
8508
8729
8025
9099
3251
8382
5495 .
9591
9671
9738
9793
9838
3875
9904
9945
9959
9909
9977
3984
9988
05
5199
5696
6736
7088
1422
7734
2531
8749
8944
9115
9265
9094
9505
95.99
9678
9744
9798
9842
90029
9946
9960
9970
9978
9989
9994
9997
05
06
5239
5325
8772
71:23
.7454
7764
8051
8315
3554
8770
2962
3279
9406
9515
9601
.9686
9750
9803
9846
3881
9909
9931
9948
9961
9971
9979
9985
9989
3922
9994
9997
07
5279
5675
8064
6443
6808
7157
3486
7794
8078
8340
8577
8790
8060
9147
9418
9756
9808
9884
9911
9932
9949
9972
9979
9989
9996
9000
07
08
5319
5714
6103
6480
6344
7190
7517
7823
3106
8305
3599
8810
2007
9162
3306
9429
9535
9625
309
9761
9812
9854
991:3
9934
9951
9963
9973
9980
3996
9990
9993
9995
9997
08
5359
5753
6141
6617
6879
7224
3549
7852
8133
8389
8621
8830
9015
9177
5019
9441
9645
9433
9706
9767
9617
9690
9916
9606
9964
9974
9961
9006
9960
9998
Common Critical Values
2
0.0
0.1
02
0.3
04
0.5
06
0.7
0.8
0.9
1.0
1.2
1.4
1.5
1.6
1.7
1.8
1.9
20
2.1
22
2.3
24
25
26
27
2.8
3.0
3.1
3.2
33
3.4
3.50 and up
2
Expert Solution

Step 1
Given that
n = 2516 , X = 1001
95% confidence interval
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