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Use the pumping lemma contraposition to prove that the following languages are not regular. The language L over alphabet Σ = {0, 1}, a number of 1's has a common factor, different than 1, with the number of O's (different than 1) 011000L, 00101 € L If for any constant nд there exists a word z = L such that (|z| ≥ NL)^[(\u,v,wZ = uvw^|uv| ≤ n₁^|v| ≥ 1)³¡±0,1,2... Z; = uv'w & L] then language L is not regular.

Use the pumping lemma contraposition to prove that the following languages are not regular. The language L over alphabet Σ = {0, 1}, a number of 1's has a common factor, different than 1, with the number of O's (different than 1) 011000L, 00101 € L If for any constant nд there exists a word z = L such that (|z| ≥ NL)^[(\u,v,wZ = uvw^|uv| ≤ n₁^|v| ≥ 1)³¡±0,1,2... Z; = uv'w & L] then language L is not regular.

Understanding Business
Understanding Business
12th Edition
ISBN:9781259929434
Author:William Nickels
Publisher:William Nickels
Chapter1: Taking Risks And Making Profits Within The Dynamic Business Environment
Section: Chapter Questions
Problem 1CE
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Use the pumping lemma contraposition to prove that the following languages are not regular. The language L over alphabet Σ = {0, 1}, a number of 1's has a common factor, different than 1, with the number of O's (different than 1) 011000L, 00101 € L If for any constant nд there exists a word z = L such that (|z| ≥ NL)^[(\u,v,wZ = uvw^|uv| ≤ n₁^|v| ≥ 1)³¡±0,1,2... Z; = uv'w & L] then language L is not regular.
Transcribed Image Text:Use the pumping lemma contraposition to prove that the following languages are not regular. The language L over alphabet Σ = {0, 1}, a number of 1's has a common factor, different than 1, with the number of O's (different than 1) 011000L, 00101 € L If for any constant nд there exists a word z = L such that (|z| ≥ NL)^[(\u,v,wZ = uvw^|uv| ≤ n₁^|v| ≥ 1)³¡±0,1,2... Z; = uv'w & L] then language L is not regular.
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