Use the information given here to answer both questions (4 and 5). For the fictitious reaction: AB → A + BSome data was collected measuring the [AB] at certain time intervals. This data was then graphed as described below.A graph of 1/[AB] versus time (s) gives a straight line with the equation: y = 0.0052x + 0.1135 and a R2 = 0.9995. A graph of ln[AB] versus time (s) gives a straight line with the equation: y = -0.0068x + 1.725 and a R2 = 0.8925. Assume the data doesn't fit a zero order reaction.What is the rate law for this reaction?Select one:a. Rate = k[AB]2b. Rate = k[A][B]c. Rate = k[AB]d. Rate = k Using the data from the previous question.What is the value of the rate constant for the given reaction?Select one:a. k = 0.0052 M-1s-1b. k = 0.0157 Ms-1c. k = 0.0068 s-1d. There is no way to determine the value of the rate constant from the given information.

Answered: Use the information given here to…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use the information given here to answer both questions (4 and 5).

For the fictitious reaction: AB → A + B

Some data was collected measuring the [AB] at certain time intervals. This data was then graphed as described below.

A graph of 1/[AB] versus time (s) gives a straight line with the equation: y = 0.0052x + 0.1135 and a R² = 0.9995. A graph of ln[AB] versus time (s) gives a straight line with the equation: y = -0.0068x + 1.725 and a R² = 0.8925. Assume the data doesn't fit a zero order reaction.

What is the rate law for this reaction?

Select one:

a. Rate = k[AB]²

b. Rate = k[A][B]

c. Rate = k[AB]

d. Rate = k

Using the data from the previous question.

What is the value of the rate constant for the given reaction?

Select one:

a. k = 0.0052 M^-1s^-1

b. k = 0.0157 Ms^-1

c. k = 0.0068 s^-1

d. There is no way to determine the value of the rate constant from the given information.

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From the given information, it is clear that the graph of 1/[AB] versus time (s) gives a straight line with the equation: y = 0.0052x + 0.1135

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