Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): (Figure 1) Completed; correct answer withheld by instructor Part G lost when 165 g of iron cools from 118° C to 51 °C Express your answer using two significant figures. J Submit Previous Answers Figure 1 of 1 Completed; correct answer withheld by instructor Substance cal/g °C J/g °C Elements Part H Aluminum, Al(s) 0.214 0.897 Copper, Cu(s) 0.0920 0.385 lost when 165 g of iron cools from 118° C to 51 °C Gold, Au(s) 0.0308 0.129 Express your answer using two significant figures. Iron, Fe(s) 0.108 0.452 Silver, Ag (s) 0.0562 0.235 cal Titanium, Ti(s) 0.125 0.523 Compounds Submit Previous Answers Ammonia, NH3(g) 0.488 2.04 Ethanol, C,HOН() 0.588 2.46 Completed; correct answer withheld by instructor 0.207 0.864 Sodium chloride, NaCI(s) Water, H20(1) 1.00 4.184 Water, H,0(s) 0.485 2.03 Provide Feedback
Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): (Figure 1) Completed; correct answer withheld by instructor Part G lost when 165 g of iron cools from 118° C to 51 °C Express your answer using two significant figures. J Submit Previous Answers Figure 1 of 1 Completed; correct answer withheld by instructor Substance cal/g °C J/g °C Elements Part H Aluminum, Al(s) 0.214 0.897 Copper, Cu(s) 0.0920 0.385 lost when 165 g of iron cools from 118° C to 51 °C Gold, Au(s) 0.0308 0.129 Express your answer using two significant figures. Iron, Fe(s) 0.108 0.452 Silver, Ag (s) 0.0562 0.235 cal Titanium, Ti(s) 0.125 0.523 Compounds Submit Previous Answers Ammonia, NH3(g) 0.488 2.04 Ethanol, C,HOН() 0.588 2.46 Completed; correct answer withheld by instructor 0.207 0.864 Sodium chloride, NaCI(s) Water, H20(1) 1.00 4.184 Water, H,0(s) 0.485 2.03 Provide Feedback
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Question
Transcribed Image Text:Use the heat equation to calculate the energy, in joules and
calories, for each of the following (see the table):
(Figure 1)
Completed; correct answer withheld by instructor
Part G
lost when 165 g of iron cools from 118° C to 51 °C
Express your answer using two significant figures.
J
Submit
Previous Answers
Figure
1 of 1
Completed; correct answer withheld by instructor
Substance
cal/g °C
J/g °C
Elements
Part H
Aluminum, Al(s)
0.214
0.897
Copper, Cu(s)
0.0920
0.385
lost when 165 g of iron cools from 118° C to 51 °C
Gold, Au(s)
0.0308
0.129
Express your answer using two significant figures.
Iron, Fe(s)
0.108
0.452
Silver, Ag(s)
0.0562
0.235
cal
Titanium, Ti(s)
0.125
0.523
Compounds
Submit
Previous Answers
Ammonia, NH3(g)
0.488
2.04
Ethanol, C,H,OH(!)
0.588
2.46
Completed; correct answer withheld by instructor
Sodium chloride, NaCI(s)
0.207
0.864
Water, H;O(!)
1.00
4.184
Water, H;O(s)
0.485
2.03
Provide Feedback
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