When 1690.0 joules of energy is added to a 140.0 gram piece of unknown substance, the temperature of the substance increases from 21.8°C to 36.8°. Calculate the specific heat capacity (Cp) for the material in the units indicated below. [Answer with 3 significant figures] Cp= 0.805 J/g °C Cp = Cp= 0.192 Cp= J/g-K cal/g °C cal/g.K
When 1690.0 joules of energy is added to a 140.0 gram piece of unknown substance, the temperature of the substance increases from 21.8°C to 36.8°. Calculate the specific heat capacity (Cp) for the material in the units indicated below. [Answer with 3 significant figures] Cp= 0.805 J/g °C Cp = Cp= 0.192 Cp= J/g-K cal/g °C cal/g.K
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**Specific Heat Capacity Calculation**
When 1690.0 joules of energy is added to a 140.0 gram piece of unknown substance, the temperature of the substance increases from 21.8°C to 36.8°C. Calculate the specific heat capacity (\(C_p\)) for the material in the units indicated below. [Answer with 3 significant figures]
- \(C_p = 0.805 \, \text{J/g°C}\)
- \(C_p = \, \text{J/g·K}\)
- \(C_p = 0.192 \, \text{cal/g°C}\)
- \(C_p = \, \text{cal/g·K}\)
[Check]
---
**Explanation:**
You will need to use the formula for calculating specific heat capacity:
\[
C_p = \frac{q}{m \Delta T}
\]
Where:
- \(q\) is the heat energy added (1690.0 joules),
- \(m\) is the mass of the substance (140.0 grams),
- \(\Delta T\) is the change in temperature (36.8°C - 21.8°C = 15.0°C).
Perform the calculations to find \(C_p\) in the specified units. Fill in the values for \(C_p\) and verify your answers.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F416ff6d2-799f-43c9-9dc0-e44c7b16bb4d%2F719929df-f97d-4333-b2a7-b442dd5085fc%2F5qkvxqy_processed.png&w=3840&q=75)
Transcribed Image Text:---
**Specific Heat Capacity Calculation**
When 1690.0 joules of energy is added to a 140.0 gram piece of unknown substance, the temperature of the substance increases from 21.8°C to 36.8°C. Calculate the specific heat capacity (\(C_p\)) for the material in the units indicated below. [Answer with 3 significant figures]
- \(C_p = 0.805 \, \text{J/g°C}\)
- \(C_p = \, \text{J/g·K}\)
- \(C_p = 0.192 \, \text{cal/g°C}\)
- \(C_p = \, \text{cal/g·K}\)
[Check]
---
**Explanation:**
You will need to use the formula for calculating specific heat capacity:
\[
C_p = \frac{q}{m \Delta T}
\]
Where:
- \(q\) is the heat energy added (1690.0 joules),
- \(m\) is the mass of the substance (140.0 grams),
- \(\Delta T\) is the change in temperature (36.8°C - 21.8°C = 15.0°C).
Perform the calculations to find \(C_p\) in the specified units. Fill in the values for \(C_p\) and verify your answers.
Expert Solution
Introduction
When heat energy is given to a system its temperature increases. This is expressed as :
Heat added = m x Cp x t
Cp=
Where m is mass of the substance , t is the change in temperature and Cp is the heat capacity of the system.
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