A 150.0 g block of lead at 100.0 °C is placed in a calorimeter with 50.0 g of water at 22.0 °C. The final temperature of the system is 26.2 °C. 1. Calculate the heat lost by the lead (Clead = 0.128 (°C × g)' 2. Calculate the heat gained by the water. (Cwater = 4.184 .) (°C x g) 3. Calculate the heat gained by the calorimeter. 1 4. Calculate the Ccalorimeter.

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A 150.0 g block of lead at 100.0 degree celsisus is placed in a calormeter with 50.0 g of water at 22.0 degrees celsisus. The final temperature of the system is 26.2 degree celsius.

Use that inforamtion above to solve questions 1-4: Picture attached below. Need help ASAP

 

A 150.0 g block of lead at 100.0 °C is placed in a calorimeter with 50.0 g of water at 22.0 °C.
The final temperature of the system is 26.2 °C.
1. Calculate the heat lost by the lead (Clead = 0.128 ).
%3D
( °C ×
2. Calculate the heat gained by the water. (Cwater = 4.184
(°C x g)
3. Calculate the heat gained by the calorimeter.
1
4. Calculate the Ccalorimeter.
Transcribed Image Text:A 150.0 g block of lead at 100.0 °C is placed in a calorimeter with 50.0 g of water at 22.0 °C. The final temperature of the system is 26.2 °C. 1. Calculate the heat lost by the lead (Clead = 0.128 ). %3D ( °C × 2. Calculate the heat gained by the water. (Cwater = 4.184 (°C x g) 3. Calculate the heat gained by the calorimeter. 1 4. Calculate the Ccalorimeter.
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