Use the given frequency distribution to find the (a) class width. (b) class midpoint of the first class. (c) class boundaries of the first class. (a) 3 O A. (b) 51 (c) 50-52 (a) 2 OC. (b) 51.5 (c) 49.5-52.5 Height (in inches) Class Frequency, f 5 50-52 53-55 56-58 59-61 62-64 00 8 12 13 11
Use the given frequency distribution to find the (a) class width. (b) class midpoint of the first class. (c) class boundaries of the first class. (a) 3 O A. (b) 51 (c) 50-52 (a) 2 OC. (b) 51.5 (c) 49.5-52.5 Height (in inches) Class Frequency, f 5 50-52 53-55 56-58 59-61 62-64 00 8 12 13 11
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![### Frequency Distribution Analysis
#### Instructions:
Use the given frequency distribution to find the:
(a) Class width
(b) Class midpoint of the first class
(c) Class boundaries of the first class
#### Data Table:
| Class | Frequency, f |
|--------|--------------|
| 50-52 | 5 |
| 53-55 | 8 |
| 56-58 | 12 |
| 59-61 | 13 |
| 62-64 | 11 |
#### Answer Choices:
- **A**.
- (a) 3
- (b) 51
- (c) 50-52
- **B**.
- (a) 3
- (b) 51
- (c) 49.5-52.5
- **C**.
- (a) 2
- (b) 51.5
- (c) 49.5-52.5
- **D**.
- (a) 2
- (b) 51.5
- (c) 50-52
#### Explanation:
To find the correct answers:
1. **Class width**: The class width is the difference between the upper boundary and the lower boundary of a class.
2. **Class midpoint**: The class midpoint is calculated by averaging the upper and lower boundaries of the class.
3. **Class boundaries**: Class boundaries are used to ensure that there are no gaps between the classes. They are calculated by adding or subtracting 0.5 from the upper and lower class limits, respectively.
Please select the appropriate answer based on the calculations described.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1784d6b6-d0da-4ca6-88bb-f1a2aff3fb92%2F5af13393-fa00-4865-ab79-c3d1b529645f%2F5bwfzai_processed.png&w=3840&q=75)
Transcribed Image Text:### Frequency Distribution Analysis
#### Instructions:
Use the given frequency distribution to find the:
(a) Class width
(b) Class midpoint of the first class
(c) Class boundaries of the first class
#### Data Table:
| Class | Frequency, f |
|--------|--------------|
| 50-52 | 5 |
| 53-55 | 8 |
| 56-58 | 12 |
| 59-61 | 13 |
| 62-64 | 11 |
#### Answer Choices:
- **A**.
- (a) 3
- (b) 51
- (c) 50-52
- **B**.
- (a) 3
- (b) 51
- (c) 49.5-52.5
- **C**.
- (a) 2
- (b) 51.5
- (c) 49.5-52.5
- **D**.
- (a) 2
- (b) 51.5
- (c) 50-52
#### Explanation:
To find the correct answers:
1. **Class width**: The class width is the difference between the upper boundary and the lower boundary of a class.
2. **Class midpoint**: The class midpoint is calculated by averaging the upper and lower boundaries of the class.
3. **Class boundaries**: Class boundaries are used to ensure that there are no gaps between the classes. They are calculated by adding or subtracting 0.5 from the upper and lower class limits, respectively.
Please select the appropriate answer based on the calculations described.
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