• Find the class boundaries of the first class and the last class • Find the class width of the frequency distribution Answer: Class width is Numbers of Miles Students Drive to School Each Day Class Frequency Class Boundaries 1.0 - 2.9 3.0 - 4.9 3 5.0 - 6.9 4 7.0 - 8.9 2 9.0 - 10.9 4 11.0 - 12.9 Hint: You can find upper class boundary by using this formula : Upper Boundary of class = ( upper limit + lower limit next class)/ 2 Example upper boundary of class 2 = 4.9 + 5.0 = 4.95 2.9 + 3.0 Similar for lower boundary, example lower boundary class 2 = = 2.95 After that you can subtract class width to find previous lower or upper class boundaries
• Find the class boundaries of the first class and the last class • Find the class width of the frequency distribution Answer: Class width is Numbers of Miles Students Drive to School Each Day Class Frequency Class Boundaries 1.0 - 2.9 3.0 - 4.9 3 5.0 - 6.9 4 7.0 - 8.9 2 9.0 - 10.9 4 11.0 - 12.9 Hint: You can find upper class boundary by using this formula : Upper Boundary of class = ( upper limit + lower limit next class)/ 2 Example upper boundary of class 2 = 4.9 + 5.0 = 4.95 2.9 + 3.0 Similar for lower boundary, example lower boundary class 2 = = 2.95 After that you can subtract class width to find previous lower or upper class boundaries
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
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![- **Find the class boundaries of the first class and the last class**
- **Find the class width of the frequency distribution**
**Answer:**
Class width is [Input Box]
---
**Table: Numbers of Miles Students Drive to School Each Day**
| Class | Frequency | Class Boundaries |
|----------|-----------|------------------|
| 1.0 - 2.9| 3 | [Input] - [Input]|
| 3.0 - 4.9| 3 | |
| 5.0 - 6.9| 4 | |
| 7.0 - 8.9| 2 | |
| 9.0 - 10.9| 4 | |
| 11.0 - 12.9| 2 | [Input] - [Input]|
---
**Hint:** You can find the upper class boundary by using this formula:
- **Upper Boundary of class = ( upper limit + lower limit next class ) / 2**
- Example upper boundary of class 2:
\[
\frac{4.9 + 5.0}{2} = 4.95
\]
- For the lower boundary, use a similar method:
- Example lower boundary of class 2:
\[
\frac{2.9 + 3.0}{2} = 2.95
\]
After finding one boundary, subtract the class width to find the previous lower or upper class boundaries.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67293246-13a3-4f7d-bd6e-c064ec0ea814%2F5dd20982-8ff6-42d1-9db6-b5f9d04d4183%2Fmlzgcih_processed.png&w=3840&q=75)
Transcribed Image Text:- **Find the class boundaries of the first class and the last class**
- **Find the class width of the frequency distribution**
**Answer:**
Class width is [Input Box]
---
**Table: Numbers of Miles Students Drive to School Each Day**
| Class | Frequency | Class Boundaries |
|----------|-----------|------------------|
| 1.0 - 2.9| 3 | [Input] - [Input]|
| 3.0 - 4.9| 3 | |
| 5.0 - 6.9| 4 | |
| 7.0 - 8.9| 2 | |
| 9.0 - 10.9| 4 | |
| 11.0 - 12.9| 2 | [Input] - [Input]|
---
**Hint:** You can find the upper class boundary by using this formula:
- **Upper Boundary of class = ( upper limit + lower limit next class ) / 2**
- Example upper boundary of class 2:
\[
\frac{4.9 + 5.0}{2} = 4.95
\]
- For the lower boundary, use a similar method:
- Example lower boundary of class 2:
\[
\frac{2.9 + 3.0}{2} = 2.95
\]
After finding one boundary, subtract the class width to find the previous lower or upper class boundaries.
Expert Solution
Step 1
| Class | Frequency | class Boundaries |
| 1.0-2.9 | 3 | |
| 3.0-4.9 | 3 | |
| 5.0-6.9 | 4 | |
| 7.0-8.9 | 2 | |
| 9.0-10.9 | 4 | |
| 11.0-12.9 | 2 |
Step by step
Solved in 3 steps
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