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4. Use the free body diagram and Newton's 2nd law to determine an expression for the Tension
in the string from the forces in the vertical direction (should depend on m, g, and 0 only).
Tcose
Tsin0
mg
Tension, T = (m)(g)(sin@)
5. In the horizontal direction the mass moves in a circular path of radius R and speed v.
Newton's Second Law here therefore tells us:
Combine this with your result from part
4 to determine an expression for v in terms g, 0, and R.

Expert Solution

Step 1

as shown in figure, in vertical direction for equilibrium net force $F_{v}$ must be zero.

net force in vertical

$F_{V} = T \cos θ - m g 0 = T \cos θ - m g T = \frac{m g}{\cos θ} - - - - - - - e q n (1)$

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