Analyzing circular motion at constant speed is an important next step after you've developed an ability to explain motions with constant acceleration (like free fall). The peculiarity of circular motion at constant speed is that the magnitude of the acceleration is constant, but the direction of the acceleration vector rotates so that it always points to the center of the circle. It's completely different than "free fall", where the acceleration's direction points down and doesn't rotate. Rotating acceleration is illustrated in the top figure. Two velocity vectors are shown: V₁ and v2. They indicate the velocities at the two ends of an arc. They have the same length v, which matches the constant speed idea. The direction changes as the ball moves around. When you subtract one vector from the other, the difference is the "velocity change vector". It always points towards the center of the circle from the middle of the arc. The "centripetal acceleration" has the magnitude a centripetal =V²/r anywhere on the circle. V2 Av Velocity change vector: Av=V₂ - V₁ r 121 V1 Sog h Swing rides at amusement parks are a popular way to experience this type of motion. The photograph captures a swing ride in motion. You can see a series of cables swung out from the top disk at an angle. At the end of each cable is a seat with a person riding the swing. The riders travel around a circle - it's fun! A swing ride is one example of a "conical pendulum". In the photograph, the lines of the cables from all the seats intersect at a vertex above the disk, and these lines form the cone. As you might expect, when the ride turns faster, the angle at the vertex of the cone gets larger. The radius of the circle also gets bigger. The vertical distance h from the vertex down to the chairs

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Chapter1: Units, Trigonometry. And Vectors
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**Features of a Pre-lab Homework**

Analyzing circular motion at constant speed is an important next step after you’ve developed an ability to explain motions with constant acceleration (like free fall). The peculiarity of circular motion at constant speed is that the magnitude of the acceleration is constant, but the direction of the acceleration vector rotates so that it always points to the center of the circle. It’s completely different than “free fall”, where the acceleration’s direction points down and doesn’t rotate. 

Rotating acceleration is illustrated in the top figure. Two velocity vectors are shown: \(v_1\) and \(v_2\). They indicate the velocities at the two ends of an arc. They have the same length \(v\), which matches the constant speed idea. The direction changes as the ball moves around. When you subtract one vector from the other, the difference is the “velocity change vector”. It always points towards the center of the circle from the middle of the arc. The “centripetal acceleration” has the magnitude \(a_{\text{centripetal}} = v^2/r\) anywhere on the circle.

Swing rides at amusement parks are a popular way to experience this type of motion. The photograph captures a swing ride in motion. You can see a series of cables swung out from the top disk at an angle. At the end of each cable is a seat with a person riding the swing. The riders travel around a circle - it’s fun!

A swing ride is one example of a “conical pendulum”. In the photograph, the lines of the cables from all the seats intersect at a vertex above the disk, and these lines form the cone. As you might expect, when the ride turns faster, the angle at the vertex of the cone gets larger. The radius of the circle also gets bigger. The vertical distance \(h\) from the vertex down to the chairs gets smaller. In terms of \(h\), the equation for the time \(T\) that it takes a rider to do one circle is \(T = 2\pi \sqrt{h/g}\), where \(g\) is the gravitational acceleration constant (about 9.8 \(m/s^2\)). It’s interesting that the equation is the same for the period of an ordinary pendulum of length \(h\) that just swings back and forth. It isn’t a coincidence, but we won’t go further. The speed \(s
Transcribed Image Text:**Features of a Pre-lab Homework** Analyzing circular motion at constant speed is an important next step after you’ve developed an ability to explain motions with constant acceleration (like free fall). The peculiarity of circular motion at constant speed is that the magnitude of the acceleration is constant, but the direction of the acceleration vector rotates so that it always points to the center of the circle. It’s completely different than “free fall”, where the acceleration’s direction points down and doesn’t rotate. Rotating acceleration is illustrated in the top figure. Two velocity vectors are shown: \(v_1\) and \(v_2\). They indicate the velocities at the two ends of an arc. They have the same length \(v\), which matches the constant speed idea. The direction changes as the ball moves around. When you subtract one vector from the other, the difference is the “velocity change vector”. It always points towards the center of the circle from the middle of the arc. The “centripetal acceleration” has the magnitude \(a_{\text{centripetal}} = v^2/r\) anywhere on the circle. Swing rides at amusement parks are a popular way to experience this type of motion. The photograph captures a swing ride in motion. You can see a series of cables swung out from the top disk at an angle. At the end of each cable is a seat with a person riding the swing. The riders travel around a circle - it’s fun! A swing ride is one example of a “conical pendulum”. In the photograph, the lines of the cables from all the seats intersect at a vertex above the disk, and these lines form the cone. As you might expect, when the ride turns faster, the angle at the vertex of the cone gets larger. The radius of the circle also gets bigger. The vertical distance \(h\) from the vertex down to the chairs gets smaller. In terms of \(h\), the equation for the time \(T\) that it takes a rider to do one circle is \(T = 2\pi \sqrt{h/g}\), where \(g\) is the gravitational acceleration constant (about 9.8 \(m/s^2\)). It’s interesting that the equation is the same for the period of an ordinary pendulum of length \(h\) that just swings back and forth. It isn’t a coincidence, but we won’t go further. The speed \(s
Problem

Scaling from the photograph and the seated size of the riders, \( h \) is about 12 meters and \( r \) is about 9 meters.

(a) What is the period \( T \) of the swing ride?

(b) What is the speed \( s \) at which the riders are moving?

(c) What is the ratio of the centripetal acceleration of the riders and the gravitational acceleration \( g \)?
Transcribed Image Text:Problem Scaling from the photograph and the seated size of the riders, \( h \) is about 12 meters and \( r \) is about 9 meters. (a) What is the period \( T \) of the swing ride? (b) What is the speed \( s \) at which the riders are moving? (c) What is the ratio of the centripetal acceleration of the riders and the gravitational acceleration \( g \)?
Expert Solution
Step 1: Height and radius of the circular wheel is given

Height h = 12m

Radius r = 9m


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